HCI H2O CI b. I| II 16. For the following reaction determine the K. Br2(g) + Cl2(g) 2 BrCl(g) K=???? Initial: 0.60 0.60 Equilibrium: 0.28 17. Hydrogen sulfide (H,S) is a contaminant commonly found in natural by reaction with oxygen to produce elemental sulfur. (8 points) 2H2S(g)+02(g)2 2S(s)+2H,0(g) For each of the following scenarios, determine whether the equilibrium w right, shift to the left or noit
HCI H2O CI b. I| II 16. For the following reaction determine the K. Br2(g) + Cl2(g) 2 BrCl(g) K=???? Initial: 0.60 0.60 Equilibrium: 0.28 17. Hydrogen sulfide (H,S) is a contaminant commonly found in natural by reaction with oxygen to produce elemental sulfur. (8 points) 2H2S(g)+02(g)2 2S(s)+2H,0(g) For each of the following scenarios, determine whether the equilibrium w right, shift to the left or noit
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Step 1
Since initial concentration of BrCl = 0
And at equilibrium its 0.28
Hence all the concentration of BrCl came from Br2 and Cl2 reacted
Since 1 M concentration of Br2 reacting will produce 2 M concentration of BrCl
Hence concentration of Br2 reacted = equilibrium concentration of BrCl / 2 = 0.28 / 2 = 0.14
Since Br2 concentration reacted = Cl2 concentration reacted as 1 mole of Br2 is reacting with 1 mole of Cl2 in the above reaction
=> Cl2 concentration reacted = 0.14
hence equilibrium concentration of Cl2 = initial concentration - reacted = 0.6 - 0.14 = 0.46
equilibrium concentration of Br2 = initial concentration - reacted = 0.6 - 0.14 = 0.46
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