HCI H2O CI b. I| II 16. For the following reaction determine the K. Br2(g) + Cl2(g) 2 BrCl(g) K=???? Initial: 0.60 0.60 Equilibrium: 0.28 17. Hydrogen sulfide (H,S) is a contaminant commonly found in natural by reaction with oxygen to produce elemental sulfur. (8 points) 2H2S(g)+02(g)2 2S(s)+2H,0(g) For each of the following scenarios, determine whether the equilibrium w right, shift to the left or noit

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16-

HCI
H2O
CI
b.
I|
II
16. For the following reaction determine the K.
Br2(g) + Cl2(g) 2 BrCl(g)
K=????
Initial:
0.60
0.60
Equilibrium:
0.28
17. Hydrogen sulfide (H,S) is a contaminant commonly found in natural
by reaction with oxygen to produce elemental sulfur. (8 points)
2H2S(g)+02(g)2 2S(s)+2H,0(g)
For each of the following scenarios, determine whether the equilibrium w
right, shift to the left or noit
Transcribed Image Text:HCI H2O CI b. I| II 16. For the following reaction determine the K. Br2(g) + Cl2(g) 2 BrCl(g) K=???? Initial: 0.60 0.60 Equilibrium: 0.28 17. Hydrogen sulfide (H,S) is a contaminant commonly found in natural by reaction with oxygen to produce elemental sulfur. (8 points) 2H2S(g)+02(g)2 2S(s)+2H,0(g) For each of the following scenarios, determine whether the equilibrium w right, shift to the left or noit
Expert Solution
Step 1

Since initial concentration of BrCl = 0 

And at equilibrium its 0.28 

Hence all the concentration of BrCl came from Br2 and Cl2 reacted 

Since 1 M concentration of Br2 reacting will produce 2 M concentration of BrCl

Hence concentration of Br2 reacted = equilibrium concentration of BrCl / 2 = 0.28 / 2 = 0.14 

Since Br2 concentration reacted = Cl2 concentration reacted as 1 mole of Br2 is reacting with 1 mole of Cl2 in the above reaction 

=> Cl2 concentration reacted = 0.14 

hence equilibrium concentration of Cl2 = initial concentration - reacted  = 0.6 - 0.14 = 0.46 

equilibrium concentration of Br2 = initial concentration - reacted = 0.6 - 0.14 = 0.46

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