At 800°C, 20.00 atm of CO2(g) is stored in a 1.00 L container. 10.00 g of C (s) is then added into the container. The CO2(g) then reacts with C(s) to form CO(g) according to the following reaction: CO2(g) + C(s) = 2CO(g) After the reaction has reached equilibrium, the mass of C (s) is reduced to 9.12 g. The molar mass of Cis 12.00 g/mol. a) Determine the partial pressure of CO at equilibrium. - b) Determine the partial pressure of CO2 at equilibrium. ( c) Write and Calculate the equilibrium constant of the above reaction.

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At 800°C, 20.00 atm of CO2(g) is stored in a 1.00 L container. 10.00 g of C (s) is then added into the
container. The CO2(g) then reacts with C(s) to form CO(g) according to the following reaction:
CO2(g) + C(s) = 2CO(g)
After the reaction has reached equilibrium, the mass of C (s) is reduced to 9.12 g. The molar mass of
C is 12.00 g/mol.
a) Determine the partial pressure of CO at equilibrium. w
b) Determine the partial pressure of CO2 at equilibrium.
c) Write and Calculate the equilibrium constant of the above reaction.
d) The container is compressed from 1.00 L to 0.50 L. Without doing any calculation, predict how
the mass of C (s) change at the end of the reaction.
In this question, the volume of the C (s) is negligible compared to the volume of the container.
Transcribed Image Text:At 800°C, 20.00 atm of CO2(g) is stored in a 1.00 L container. 10.00 g of C (s) is then added into the container. The CO2(g) then reacts with C(s) to form CO(g) according to the following reaction: CO2(g) + C(s) = 2CO(g) After the reaction has reached equilibrium, the mass of C (s) is reduced to 9.12 g. The molar mass of C is 12.00 g/mol. a) Determine the partial pressure of CO at equilibrium. w b) Determine the partial pressure of CO2 at equilibrium. c) Write and Calculate the equilibrium constant of the above reaction. d) The container is compressed from 1.00 L to 0.50 L. Without doing any calculation, predict how the mass of C (s) change at the end of the reaction. In this question, the volume of the C (s) is negligible compared to the volume of the container.
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