At 800 K, the equilibrium constant for the following reaction is K. = 3.1 x 10-5: I2 (g) = 21(g) If an equilibrium mixture in a 10.0-L vessel contains 2.69 × 10¬²g of I(g), how many grams of I2 are in the mixture? Express your answer in grams to two significant figures.

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**Equilibrium and Reaction Dynamics**

At 800 K, the equilibrium constant for the following reaction is \( K_c = 3.1 \times 10^{-5} \):

\[
\text{I}_2(g) \rightleftharpoons 2\text{I}(g)
\]

**Problem Statement:**

If an equilibrium mixture in a 10.0-L vessel contains \( 2.69 \times 10^{-2} \, \text{g} \) of \(\text{I}(g)\), how many grams of \(\text{I}_2\) are in the mixture?

**Instructions:**

Express your answer in grams to two significant figures.
Transcribed Image Text:**Equilibrium and Reaction Dynamics** At 800 K, the equilibrium constant for the following reaction is \( K_c = 3.1 \times 10^{-5} \): \[ \text{I}_2(g) \rightleftharpoons 2\text{I}(g) \] **Problem Statement:** If an equilibrium mixture in a 10.0-L vessel contains \( 2.69 \times 10^{-2} \, \text{g} \) of \(\text{I}(g)\), how many grams of \(\text{I}_2\) are in the mixture? **Instructions:** Express your answer in grams to two significant figures.
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