### Decomposition of Hydrogen Iodide at 800 KAt 800 K, hydrogen iodide (HI) can decompose into hydrogen (H₂) and iodine (I₂) gases according to the equilibrium reaction:\[ 2HI(g) \rightleftharpoons I_2(g) + H_2(g) \]At this temperature, the equilibrium constant, \( K \), is 0.0169. Given this information, we are asked to determine the partial pressures of hydrogen and iodine at equilibrium if initially a sealed flask at 800 K contains only HI at a pressure of 0.226 atm.The problem can be broken down into the following steps:1. **Initial Condition:** - Initial pressure of HI, \( P_{HI} \): 0.226 atm. - Initial pressure of H₂ and I₂: 0 atm (since initially only HI is present).2. **Change at Equilibrium:** - Let the change in pressure of HI be \( -2x \) (since 2 moles of HI produce 1 mole each of H₂ and I₂). - The change in pressure of both H₂ and I₂ will be \( +x \).3. **Equilibrium Condition:** - Equilibrium pressure of HI: \( 0.226 - 2x \) atm. - Equilibrium pressure of H₂: \( x \) atm. - Equilibrium pressure of I₂: \( x \) atm.4. **Equilibrium Expression:** \[ K = \frac{(P_{I2})(P_{H2})}{(P_{HI})^2} \] Substituting the equilibrium conditions: \[ 0.0169 = \frac{(x)(x)}{(0.226 - 2x)^2} \]5. **Solving for \( x \):** This equation needs to be solved to find the value of \( x \) which will give us the partial pressures at equilibrium. 6. **Substitute \( x \) into Equilibrium Pressures:** - Partial pressure of hydrogen \( P_{H₂} = x \) atm. - Partial pressure of iodine \( P_{I₂} = x \) atm.### User Interaction**Question:**What are the partial pressures at equilibrium of the hydrogen and

Given reaction is : 2HI (g) <----------------> I2 (g) + H2 (g) Value of equilibrium constant…

At 800 K, hydrogen iodide can decompose into hydrogen and iodine gases. 2HI(9) 2(9) +H2 (g) At this temperature, K = 0.0169. What are the partial pressures at equilibrium of the hydrogen and iodine if initially a sealed flask at 800 K contains only HI at a pressure of 0.226 atm? Partial pressure of hydrogen = atm Partial pressure of iodine = atm

At 800 K, hydrogen iodide can decompose into hydrogen and iodine gases. 2HI(9) 2(9) +H2 (g) At this temperature, K = 0.0169. What are the partial pressures at equilibrium of the hydrogen and iodine if initially a sealed flask at 800 K contains only HI at a pressure of 0.226 atm? Partial pressure of hydrogen = atm Partial pressure of iodine = atm

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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