= At 7.42 °C the concentration equilibrium constant K 4.7 for a certain reaction. Here are some facts about the reaction: • Some of the reactants are liquids and solids. •If the reaction is run at constant pressure, 83.0 kJ/mol of heat are absorbed. The net change in moles of gases is 2. Using these facts, can you calculate K at -20. °C? x10 ○ Yes. O No. If you said yes, then enter your answer at right. Round it to 2 significant digits. n If you said no, can you at least decide whether K at -20. °C will be bigger or smaller than K at -7.42 °C? Yes, and K will be bigger. Yes, and K will be smaller. No.

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At -7.42 °C the concentration equilibrium constant K = 4.7 for a certain reaction.
Here are some facts about the reaction:
. Some of the reactants are liquids and solids.
If the reaction is run at constant pressure, 83.0 kJ/mol of heat are absorbed.
The net change in moles of gases is 2.
●
Using these facts, can you calculate K at -20. °C?
If you said yes, then enter your answer at right. Round it to
2 significant digits.
If you said no, can you at least decide whether Kat
-20. °C will be bigger or smaller than Kat -7.42 °C?
O Yes.
O No.
0
Yes, and K will be
bigger.
Yes, and K will be
smaller.
O No.
0x1.2
X
Toc
Transcribed Image Text:At -7.42 °C the concentration equilibrium constant K = 4.7 for a certain reaction. Here are some facts about the reaction: . Some of the reactants are liquids and solids. If the reaction is run at constant pressure, 83.0 kJ/mol of heat are absorbed. The net change in moles of gases is 2. ● Using these facts, can you calculate K at -20. °C? If you said yes, then enter your answer at right. Round it to 2 significant digits. If you said no, can you at least decide whether Kat -20. °C will be bigger or smaller than Kat -7.42 °C? O Yes. O No. 0 Yes, and K will be bigger. Yes, and K will be smaller. O No. 0x1.2 X Toc
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