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At 430°C, 4.20 mol of HI in a 9.60 L reaction vessel reaches equilibrium according to the following equation: H2(g) + 12(g) → 2HI(g) At equilibrium, [H2] = 0.0470 M and [HI] = 0.344 M. What is the value of Ko for this reaction? %3D Kc = number or fraction only

At 430°C, 4.20 mol of HI in a 9.60 L reaction vessel reaches equilibrium according to the following equation: H2(g) + 12(g) → 2HI(g) At equilibrium, [H2] = 0.0470 M and [HI] = 0.344 M. What is the value of Ko for this reaction? %3D Kc = number or fraction only

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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At 430°C, 4.20 mol of HI in a 9.60 L reaction vessel reaches equilibrium according to the following equation: H2(g) + 12(g) → 2HI(g) At equilibrium, [H2] = 0.0470 M and [HI] = 0.344 M. What is the value of K, for this reaction? Kc = number or fraction only
Transcribed Image Text:At 430°C, 4.20 mol of HI in a 9.60 L reaction vessel reaches equilibrium according to the following equation: H2(g) + 12(g) → 2HI(g) At equilibrium, [H2] = 0.0470 M and [HI] = 0.344 M. What is the value of K, for this reaction? Kc = number or fraction only
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