At 35°C, K = 2.1 × 10-5for the reaction2 NOCI(g) – 2 NO(g)+ Cl2 (9)Calculate the concentrations of all species at equilibrium for each of the following original mixtures.a. 3.6 moles of pure NOCI in a 2.0-L flask[NOCI] =M[NO] =M[Cl2] =Mb. 1.0 mole of NOCI and 1.0 mole of NO in a 1.0-L flask[NOCI] =M[NO] =M[Cl2] =Mc. 2.8 mole of NOCI and 1.0 mole of Cl2 in a 1.0-L flask[NOCI] =M%3D[NO] :M%3D[Cl2] =M

We are given a reaction., 2NOCl(g) <===> 2NO(g) + Cl2(g) Value for K = 2.1 × 10-5 at 35 ℃

At 35°C, K = 2.1 x 10° for the reaction 2 NOCI(9) = 2 NO(g) + Cl2 (g) Calculate the concentrations of all species at equilibrium for each of the following original mixtures. a. 3.6 moles of pure NOC1 in a 2.0-L flask [NOCI] M [NO] M [Cl2] = M b. 1.0 mole of NOCI and 1.0 mole of NO in a 1.0-L flask [NOCI] %3D M [NO] = M [Cl2] M c. 2.8 mole of NOCI and 1.0 mole of Cl2 in a 1.0-L flask [NOCI] M [NO] [Cl2] = M

At 35°C, K = 2.1 x 10° for the reaction 2 NOCI(9) = 2 NO(g) + Cl2 (g) Calculate the concentrations of all species at equilibrium for each of the following original mixtures. a. 3.6 moles of pure NOC1 in a 2.0-L flask [NOCI] M [NO] M [Cl2] = M b. 1.0 mole of NOCI and 1.0 mole of NO in a 1.0-L flask [NOCI] %3D M [NO] = M [Cl2] M c. 2.8 mole of NOCI and 1.0 mole of Cl2 in a 1.0-L flask [NOCI] M [NO] [Cl2] = M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

At 35°C, K = 2.1 × 10-5
for the reaction
2 NOCI(g) – 2 NO(g)+ Cl2 (9)
Calculate the concentrations of all species at equilibrium for each of the following original mixtures.
a. 3.6 moles of pure NOCI in a 2.0-L flask
[NOCI] =
M
[NO] =
M
[Cl2] =
M
b. 1.0 mole of NOCI and 1.0 mole of NO in a 1.0-L flask
[NOCI] =
M
[NO] =
M
[Cl2] =
M
c. 2.8 mole of NOCI and 1.0 mole of Cl2 in a 1.0-L flask
[NOCI] =
M
%3D
[NO] :
M
%3D
[Cl2] =
M

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