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At 25.0° C, a 10.00 L vessel is filled with 5.25 moles of Gas A and 5.15 moles of Gas B. What is the total pressure in atm?

At 25.0° C, a 10.00 L vessel is filled with 5.25 moles of Gas A and 5.15 moles of Gas B. What is the total pressure in atm?

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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**Chemistry Question:** **Question 19 of 50** At 25.0°C, a 10.00 L vessel is filled with 5.25 moles of Gas A and 5.15 moles of Gas B. What is the total pressure in atm? **Answer Input Section:** - The solution requires input of the total pressure in atm. - The input is done using a numeric keypad displayed on the screen. **Explanation:** To solve this problem, apply the ideal gas law: \[ PV = nRT \] Where: - \( P \) is the pressure, - \( V \) is the volume (10.00 L), - \( n \) is the total number of moles of gas (5.25 + 5.15 = 10.40 moles), - \( R \) is the ideal gas constant (0.0821 L·atm/mol·K), - \( T \) is the temperature in Kelvin (25°C + 273.15 = 298.15 K). Plug in the values to find \( P \).
Transcribed Image Text:**Chemistry Question:** **Question 19 of 50** At 25.0°C, a 10.00 L vessel is filled with 5.25 moles of Gas A and 5.15 moles of Gas B. What is the total pressure in atm? **Answer Input Section:** - The solution requires input of the total pressure in atm. - The input is done using a numeric keypad displayed on the screen. **Explanation:** To solve this problem, apply the ideal gas law: \[ PV = nRT \] Where: - \( P \) is the pressure, - \( V \) is the volume (10.00 L), - \( n \) is the total number of moles of gas (5.25 + 5.15 = 10.40 moles), - \( R \) is the ideal gas constant (0.0821 L·atm/mol·K), - \( T \) is the temperature in Kelvin (25°C + 273.15 = 298.15 K). Plug in the values to find \( P \).
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