Assuming that the vibrations of a 35Cl2 molecle are equivalent to those of a harmonic oscillator with a force constant kf = 329 Nm-1, calculate the zero-point energy of vibration of this molecule
Assuming that the vibrations of a 35Cl2 molecle are equivalent to those of a harmonic oscillator with a force constant kf = 329 Nm-1, calculate the zero-point energy of vibration of this molecule
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Assuming that the vibrations of a 35Cl2 molecle are equivalent to those of a harmonic oscillator with a force constant kf = 329 Nm-1, calculate the zero-point energy of vibration of this molecule. Use m(35Cl) = 34.9688mu. Show full and complete procedure in a clear way. DO NOT SKIP ANY STEP
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