Assuming that the percent of uncertainty in the calculated molar mass is the same as the percent of uncertainty in the temperature change, calculate the uncertainty in the molar mass. Could the chemist unequivocally state that the substance is cocaine? For example, is the uncertainty small enough to distinguish cocaine from codeine (C18H21NO3, molar mass = 299.36 g/mol)?
Assuming that the percent of uncertainty in the calculated molar mass is the same as the percent of uncertainty in the temperature change, calculate the uncertainty in the molar mass. Could the chemist unequivocally state that the substance is cocaine? For example, is the uncertainty small enough to distinguish cocaine from codeine (C18H21NO3, molar mass = 299.36 g/mol)?
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Assuming that the percent of uncertainty in the calculated molar mass is the same as the percent of uncertainty in the temperature change, calculate the uncertainty in the molar mass.
Could the chemist unequivocally state that the substance is cocaine? For example, is the uncertainty small enough to distinguish cocaine from codeine (C18H21NO3, molar mass = 299.36 g/mol)?

Transcribed Image Text:### Analyzing the Freezing Point Depression of a Suspected Cocaine Sample
**Context:**
A forensic chemist is tasked with analyzing a white solid that is suspected to be pure cocaine. The molecular formula of cocaine is \( C_{17}H_{21}NO_4 \) with a molar mass of 303.35 g/mol.
**Procedure:**
The chemist dissolves 1.22 ± 0.01 g of the white solid in 15.60 ± 0.01 g of benzene. The purpose is to observe the freezing point depression to gather evidence about the identity of the substance.
**Observation:**
The freezing point of the benzene solution decreases by 1.32 ± 0.04°C upon completing the procedure.
**Summary:**
- **White Solid:** Suspected to be cocaine (\( C_{17}H_{21}NO_4 \))
- **Molar Mass of Suspected Cocaine:** 303.35 g/mol
- **Mass of Solid Dissolved:** 1.22 ± 0.01 g
- **Mass of Benzene:** 15.60 ± 0.01 g
- **Freezing Point Depression Observed:** 1.32 ± 0.04°C
This information provides essential data for the chemist to calculate the molality of the solution and, subsequently, to use freezing point depression constants to verify the identity of the white solid.
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