Assuming one uses 1-equivalent of t-butyl alcohol, why is it difficult to stop the reaction at the mono-alkylated product (1-t-butyl-2,5-dimethoxy benzene)?

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Assuming one uses 1-equivalent of t-butyl alcohol, why is it difficult to stop the reaction at the mono-alkylated product (1-t-butyl-2,5-dimethoxy benzene)?

(CH), CОН
LOCH3
1-еquivalent
H3C CH3
H3C
H3CCH3
H3C
H3CO
minor product
LOCH3
LOCH3
H3CO
H,SO4
H3CO
CH3
H3CCH3
major product
Transcribed Image Text:(CH), CОН LOCH3 1-еquivalent H3C CH3 H3C H3CCH3 H3C H3CO minor product LOCH3 LOCH3 H3CO H,SO4 H3CO CH3 H3CCH3 major product
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Since methoxy group is an activating group hence substitution occurs at Ortho position to methoxy group.

Since both methoxy group and tertiary butyl group up in the mono alkylated product are electron donating groups hence benzene ring is more electron rich so further substitution occurs at Ortho position to methoxy group.

Whereas in ethyl benzoic acid, carboxylic acid group is is electron withdrawing group hence it decreases the electron density in the benzene ring hence second alkylation is not possible.

Alkylation at meta position to carboxylic acid group.

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