Assuming 95.0% efficiency for the conversion of electrical power by the motor, what current must the 12.0-V batteries of a 828-kg electric car be able to supply to do the following? (a) accelerate from rest to 25.0 m/s in 1.00 min 378.3 (b) climb a 200-m high hill in 2.00 min at a constant 25.0 m/s speed while exerting 433 N of force to overcome air resistance and friction 1.94e3 In this case, 95% of the power supplied by the motor goes into increasing the potential energy and into the work done against air friction. How is work done related to the applied force and distance traveled? A

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Assuming 95.0% efficiency for the conversion of electrical power by the motor, what current must the 12.0-V batteries of a 828-kg electric car be able to supply to do the following?
(a) accelerate from rest to 25.0 m/s in 1.00 min
378.3
A.
(b) climb a 200-m high hill in 2.00 min at a constant 25.0 m/s speed while exerting 433 N of force to overcome air resistance and friction
1.94e3
In this case, 95% of the power supplied by the motor goes into increasing the potential energy and into the work done against air friction. How is work done related to the applied force and distance traveled? A
Transcribed Image Text:Assuming 95.0% efficiency for the conversion of electrical power by the motor, what current must the 12.0-V batteries of a 828-kg electric car be able to supply to do the following? (a) accelerate from rest to 25.0 m/s in 1.00 min 378.3 A. (b) climb a 200-m high hill in 2.00 min at a constant 25.0 m/s speed while exerting 433 N of force to overcome air resistance and friction 1.94e3 In this case, 95% of the power supplied by the motor goes into increasing the potential energy and into the work done against air friction. How is work done related to the applied force and distance traveled? A
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