Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter10: Solutions
Section: Chapter Questions
Problem 39QAP: Calculate the freezing point and normal boiling points of each of the following aqueous solutions....
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Question
Assuming 100% dissociation, calculate the freezing point (Tf) and boiling point (Tb) of 2.17 m Na2SO4(aq).
Colligative constants can be found in the chempendix.
![Constants for freezing-point depression and boiling-point elevation calculations at 1 atm:
Kf value* Normal freezing K , value Normal boiling
(°C/ m )
Solvent
Formula
(°C/ m )
point ( °C)
point ( °C)
water
H 20
1.86
0.00
0.512
100.00
benzene
C 6 H 6
5.12
5.49
2.53
80.1
суclohexane C6 Н 12
C 2 H 6 0
20.8
6.59
2.92
80.7
ethanol
1.99
-117.3
1.22
78.4
carbon
CCI 4
29.8
-22.9
5.03
76.8
tetrachloride
camphor
С 10 Н 160 37.8
176](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F214a1152-ccda-43e7-9936-4a2ae323f75a%2Fa7cb9f03-bb1c-4be9-a5de-3e61eabdfa01%2F6gnnyt_processed.png&w=3840&q=75)
Transcribed Image Text:Constants for freezing-point depression and boiling-point elevation calculations at 1 atm:
Kf value* Normal freezing K , value Normal boiling
(°C/ m )
Solvent
Formula
(°C/ m )
point ( °C)
point ( °C)
water
H 20
1.86
0.00
0.512
100.00
benzene
C 6 H 6
5.12
5.49
2.53
80.1
суclohexane C6 Н 12
C 2 H 6 0
20.8
6.59
2.92
80.7
ethanol
1.99
-117.3
1.22
78.4
carbon
CCI 4
29.8
-22.9
5.03
76.8
tetrachloride
camphor
С 10 Н 160 37.8
176
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