Assume the three blocks (m1 = 1.0 kg, m2 = 2.0 kg, and m3 = 4.0 kg) portrayed in the figure below move on a frictionless surface and a force F = 48 N acts as shown on the 4.0-kg block. (a) Determine the acceleration given this system. m/s2 (to the right) (b) Determine the tension in the cord connecting the 4.0-kg and the 1.0-kg blocks. N (c) Determine the force exerted by the 1.0-kg block on the 2.0-kg block. N

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A: The below represents the free body diagram of the pulley having mass on the either sides.

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Q: m3 m2

A: Given m1 = 1 kgm2 = 2 kgm3 = 3.5 kg Force acting on block of mass 3.5 kg F = 34 N

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Q: ee blocks (m, =1.0 kg, m, = 2.0 kg, and 4.0 kg) portrayed in the figure below move on a frictionless…

A: m1= 1 kg m2= 2 kg m3= 3 kg force = F = 38 N

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Q: Assume the three blocks (m₁ = 1.0 kg, m₂ = 2.0 kg, and m3 = 4.0 kg) portrayed in the figure below…

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A: Given: part (a) force applied, Fa = 90 N part (b) The coefficients of friction are μs =0.57 and μk =…

Q: #3) Draw the Free Body Diagram for each case listed below. Remember the length of the arrows…

A: N is normal froce from bottom surfaceF is applied forcemg is weightF = frictionN = mg

Q: Assume the three blocks (m₁ = 1.0 kg, m₂ = 2.0 kg, and m3 = 4.0 kg) portrayed in the figure below…

A: Given Data: Mass 1 (m1) = 1.0 kg.Mass 2 (m2) = 2.0 kg.Mass 3 (m3) = 4.0 kg.Force (F) = 46 N. To…

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Q: Assume the three blocks (m, = 1.0 kg, m, = 2.0 kg, and m, = 3.5 kg) portrayed in the figure below…

A: Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and…

Q: Assume the three blocks (m₁ = 1.0 kg, m₂ = 2.0 kg, and m₂ = 4.0 kg) portrayed in the figure below…

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Q: Assume the three blocks (m, = 1.0 kg, m, = 2.0 kg, and mz = 3.5 kg) portrayed in the figure below…

A: Here,as given :m1=1 kgm2=2 kgm3=3.5 kgF=48 N

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A: acceleratin = F/m

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Q: Question 12 Take a look at this image. Two people are pushing a box in the opposite direction: one…

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Q: = 1.0 kg, m2 = 2.0 kg, and m3 = 4.0 kg) portrayed in the figure below move on a frictionless surface…

A: a] Acceleration a = F/m = 36/[1+2+2.5] = 6.545 m/s^2

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A: Write the given values of this problem: μk=0.2m1=2 kgm2=6 kgθ=55°

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Q: packing crates of masses m1 = 10.0 kg and m2 = 4.00 kg are connected by a light string that passes…

A: According to Newton's second law F = ma Acceleration a = F/a

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A: Given,m3 = 8.0 kgm2 = 4.0 kgm1 = 10.0 kgθ = 20°coefficient of kinetic friction, μ = 0.150

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Q: Assume the three blocks portrayed in the figure below move on a frictionless surface and a force F =…

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Q: Assume the three blocks (m₁ = 1.0 kg, m₂ = 2.0 kg, and m3 = 3.5 kg) portrayed in the figure below…

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