To hoist himself into a tree, a 72.0-kg man ties one end of a nylon rope around his waist and throws the other end over a branch of the Cree. He then pulls downward on the free end of the rope with a force of 365 N. Neglect any friction between the rope and the branch, and determine the man's upward acceleration. Use g = 9.80 m/sec². a= i
To hoist himself into a tree, a 72.0-kg man ties one end of a nylon rope around his waist and throws the other end over a branch of the Cree. He then pulls downward on the free end of the rope with a force of 365 N. Neglect any friction between the rope and the branch, and determine the man's upward acceleration. Use g = 9.80 m/sec². a= i
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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To hoist himself into a tree, a 72.0-kg man ties one end of a nylon rope around his waist and throws the other end over a branch of the tree. He then pulls downward on the free end of the rope with a force of 365 N. Neglect any friction between the rope and the branch, and determine the man’s upward acceleration. Use \( g = 9.80 \, \text{m/sec}^2 \).
\[ a = \]
*Input box for acceleration value*
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There are no graphs or diagrams associated with this problem. The text provides a clear scenario for the physics problem involving forces, mass, gravity, and acceleration. To solve the problem, one would typically use Newton's Second Law of Motion.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5e20d9b6-0c20-477e-99bf-00fa906d88b6%2Fab1dadba-657c-4778-b20c-2291659ee854%2F9ebqn7l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Current Attempt in Progress**
To hoist himself into a tree, a 72.0-kg man ties one end of a nylon rope around his waist and throws the other end over a branch of the tree. He then pulls downward on the free end of the rope with a force of 365 N. Neglect any friction between the rope and the branch, and determine the man’s upward acceleration. Use \( g = 9.80 \, \text{m/sec}^2 \).
\[ a = \]
*Input box for acceleration value*
**Resources**
- eTextbook and Media
- GO Tutorial
**Explanation of any graphs or diagrams:**
There are no graphs or diagrams associated with this problem. The text provides a clear scenario for the physics problem involving forces, mass, gravity, and acceleration. To solve the problem, one would typically use Newton's Second Law of Motion.
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