To hoist himself into a tree, a 72.0-kg man ties one end of a nylon rope around his waist and throws the other end over a branch of the Cree. He then pulls downward on the free end of the rope with a force of 365 N. Neglect any friction between the rope and the branch, and determine the man's upward acceleration. Use g = 9.80 m/sec². a= i

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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To hoist himself into a tree, a 72.0-kg man ties one end of a nylon rope around his waist and throws the other end over a branch of the tree. He then pulls downward on the free end of the rope with a force of 365 N. Neglect any friction between the rope and the branch, and determine the man’s upward acceleration. Use \( g = 9.80 \, \text{m/sec}^2 \).

\[ a = \]

*Input box for acceleration value*

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**Explanation of any graphs or diagrams:**
There are no graphs or diagrams associated with this problem. The text provides a clear scenario for the physics problem involving forces, mass, gravity, and acceleration. To solve the problem, one would typically use Newton's Second Law of Motion.
Transcribed Image Text:**Current Attempt in Progress** To hoist himself into a tree, a 72.0-kg man ties one end of a nylon rope around his waist and throws the other end over a branch of the tree. He then pulls downward on the free end of the rope with a force of 365 N. Neglect any friction between the rope and the branch, and determine the man’s upward acceleration. Use \( g = 9.80 \, \text{m/sec}^2 \). \[ a = \] *Input box for acceleration value* **Resources** - eTextbook and Media - GO Tutorial **Explanation of any graphs or diagrams:** There are no graphs or diagrams associated with this problem. The text provides a clear scenario for the physics problem involving forces, mass, gravity, and acceleration. To solve the problem, one would typically use Newton's Second Law of Motion.
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