Assume the followingString s,t,h,a,n,e;int i;h = “Hello”;s = “How are you?”a = “abc”;n = null;e = “”;Give the values of the following expressions, or illegal1. h.length()2. h.substring(1)3. h.toUpperCase()4. h.toUpperCase().toLowerCase()5. h.indexOf("H")6. h.startsWith("ell")7. "Tomorrow".indexOf("o")8. "Tomorrow".indexOf("o", 3)9. "Tomorrow".lastIndexOf('o')10. "a = \"" + a + "\""11. (a.length() + a).startsWith("a")12. a.length() + a.startsWith("a")13. ">>>" + a.length() + a.startsWith("a")14. a.substring(1,3).equals("bc")15. a.substring(1,3) == "bc"16. "a".compareTo("c")17. "a".compareTo("A")18. s.trim().charAt(2)Provide output screenshots Assume the followingString s.t.h.a.n,e;int i;h = "Hello";s = "How are you?"a = "abc";n= null;e = ";Give the values of the following expressions, or illegal1. h.length()2. h.substring(1)3. h.toUpperCase()4. h.toUpperCase().toLowerCase()5. h.indexOf("H")6. h.startsWith("ell")7. "Tomorrow".indexOf("o")8. "Tomorrow".indexOf("o", 3)9. "Tomorrow".lastIndexOf('o')10. "a = \"" + a + "\"11. (a.length() + a). starts With("a")12. a.length() + a.startsWith("a")13. ">>>" + a.length() + a.starts With("a")14. a.substring(1,3).equals("bc")15. a.substring(1,3) ="bc"16. "a".compareTo("c")17. "a".compareTo("A")18. s.trim().charAt(2)

Program: public class MyClass { public static void main(String args[]) { String…

Answered: Assume the following String…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Assume the following
String s,t,h,a,n,e;
int i;
h = “Hello”;
s = “How are you?”
a = “abc”;
n = null;
e = “”;
Give the values of the following expressions, or illegal
1. h.length()
2. h.substring(1)
3. h.toUpperCase()
4. h.toUpperCase().toLowerCase()
5. h.indexOf("H")
6. h.startsWith("ell")
7. "Tomorrow".indexOf("o")
8. "Tomorrow".indexOf("o", 3)
9. "Tomorrow".lastIndexOf('o')
10. "a = \"" + a + "\""
11. (a.length() + a).startsWith("a")
12. a.length() + a.startsWith("a")
13. ">>>" + a.length() + a.startsWith("a")
14. a.substring(1,3).equals("bc")
15. a.substring(1,3) == "bc"
16. "a".compareTo("c")
17. "a".compareTo("A")
18. s.trim().charAt(2)

Provide output screenshots

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