Assume the cost of an extended 100,000 mile warranty for a particular SUV follows the normal distributiorn with a mean of $1,210 and a standard deviation of S70. Complete parts (a) through (d) below. a) Determine the interval of warranty costs from various companies that are one standard deviation around the mean. The interval of warranty costs that are one standard deviation around the mean ranges from S to S (Type integers or decimals. Use ascending order.) b) Determine the interval of waranty costs from various companies that are two standard deviations around the mean. The interval of warranty costs that are two standard deviations around the mean ranges from S to S (Type integers or decimals. Use ascending order.) c) Determine the interval of warranty costs from various companies that are three standard deviations around the mean. The interval of warranty costs that are three standard deviations around the mean ranges from S to S (Type integers or decimals. Use ascending order.) d) An extended 100.000 mile warranty for this type of vehicle is advertised at S1.490. Based on the previous results, what conclusions can you make? O A. The $1 490 cost of this warranty is slightly higher than average due to the fact that it is more than three standard deviations above the mean. O B. The $1.490 cost of this warranty must be an error in the advertisement because a data value cannot be more than three standard deviations from the mean. OC. The $1,490 cost of this warranty is much higher than average due to the fact that it is more than three standard deviations above the mean. O D. This warranty is better quality than warranties offered by competing companies due to the fact that it is more than three standard deviations above the mean.