Assume that \( X \) is a binomial random variable with \( n = 5 \) and \( p = 0.35 \). Calculate \( P(X \leq 1) \).- ○ 0.3124- ○ 0.1160- ○ 0.4284(Note: There are no graphs or diagrams in this image.)

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Answered: Assume that X is a binomial random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose a simple random sample of n= 50 is obtained from a population whose size is N=10,000 and whose population proportion with a specified characteristic is p=0.4. What is the probability of obtaining x=17 if you were individuals with the characteristic ? That is, what is P( p̂ ≤0.34)?
Suppose a random variable, x, arises from a binomial experiment with p = 0.26, n = 15. Find P(x ≤ 3): (Give answer as a decimal correct to four decimal places.)Find P(x ≥ 9): (Give answer as a decimal correct to four decimal places.)Find P(x = 7): (Give answer as a decimal correct to four decimal places.)
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If X is a binomial random variable and if np 2 10 and n (1-p) > 10, then X is approximately normal with Hy = (Choose one) and oy = np 1-p np
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2. Let x be a binomial random variable with n=20 and p=.3. Which of the following gives p(x = 13)? • (a) Use binomial table for n=20, p=0.3, and k = 13 • (b) Use binomial table for n=20, p=0.3, and k = 12 • (c) Subtract (b) from (a), i.e. p(x= 13) = p(x ≤ 13) – p(x ≤ 12) PLEASE SHOW ME HOW TO DO IT SO I CAN LEARN IT?
Assume that a random variable Y has a mean of zero and standard deviation of one. Calculate the expected value of X1 and X2 if they are defined as below. X1 = Sigma+ Mu X2 = Sigma(Y+Mu)
An event is biased such that an outcome "x" is thrice as likely to occur as "y". Find the expected value of "y" outcomes if the event happened twice given that "x" and "y" are discrete random variables with a unit value of 1 and both of them are the only possible outcomes of the said event. Select the correct response.: 1/2 none of these 1/4 1/3 1/5
10. Let x be a binomial random variable with n = 150 and p = 0.4. Use the normal approximation to find the following. a) P(48 69) P(X>69) = 1- P(X = 69.5) = 1−ø(- c) P(X ≤ 70) 70.5-60. 69.5–60. 6 P(X <=70) = P(X = 70.5) = (- -) = = 0.9599 -) = 0.0571
Suppose that Y Binomial(n, p) (that is, discrete random variable Y has a Binomial distribution with parameters n and p, where n is a (strictly) positive integer, and 0 < p< 1).
2. Use the normal approximation to the binomial with n=10 and p=0.5 to find the probability P(X27)

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Assume that X is a binomial random variable with n= 5 and p = .35. Calculate P(X ≤ 1) O 0.3124 0.1160 0.4284