Assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value t/2, (b) find the critical value z2, or (c) state that neither the normal distribution nor the t distribution applies. Here are summary statistics for randomly selected weights of newborn girls: n= 214, x = 33.8 hg, s = 6.8 hg. The confidence level is 90%. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. tu/2 =U (Round to two decimal places as needed.) OB. Za12 (Round to two decimal places as needed.) OC. Neither the normal distribution nor the t distribution applies.

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**Constructing a Confidence Interval**

Assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value \( t_{\alpha / 2} \), (b) find the critical value \( z_{\alpha / 2} \), or (c) state that neither the normal distribution nor the t distribution applies.

### Summary Statistics
Here are summary statistics for randomly selected weights of newborn girls:
- Sample size \( n = 214 \)
- Sample mean \( \overline{x} = 33.8 \) hg
- Sample standard deviation \( s = 6.8 \) hg
- Confidence level is 90%.

### Options:
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.

#### A. \( t_{\alpha / 2} = \) 
(Round to two decimal places as needed.)

#### B. \( z_{\alpha / 2} = \)
(Round to two decimal places as needed.)

#### C. Neither the normal distribution nor the t distribution applies.

### Explanation:
Use the appropriate distribution to find the critical value needed for constructing the confidence interval based on the given statistics and confidence level. 

For option A, if the sample size is small or the population standard deviation is unknown, and the data is approximately normally distributed, you would use the t-distribution.

For option B, if the sample size is large, typically \( n > 30 \), and/or the population standard deviation is known, you would use the z-distribution.

Option C would apply if neither distribution is appropriate for the given data.
Transcribed Image Text:**Constructing a Confidence Interval** Assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value \( t_{\alpha / 2} \), (b) find the critical value \( z_{\alpha / 2} \), or (c) state that neither the normal distribution nor the t distribution applies. ### Summary Statistics Here are summary statistics for randomly selected weights of newborn girls: - Sample size \( n = 214 \) - Sample mean \( \overline{x} = 33.8 \) hg - Sample standard deviation \( s = 6.8 \) hg - Confidence level is 90%. ### Options: Select the correct choice below and, if necessary, fill in the answer box to complete your choice. #### A. \( t_{\alpha / 2} = \) (Round to two decimal places as needed.) #### B. \( z_{\alpha / 2} = \) (Round to two decimal places as needed.) #### C. Neither the normal distribution nor the t distribution applies. ### Explanation: Use the appropriate distribution to find the critical value needed for constructing the confidence interval based on the given statistics and confidence level. For option A, if the sample size is small or the population standard deviation is unknown, and the data is approximately normally distributed, you would use the t-distribution. For option B, if the sample size is large, typically \( n > 30 \), and/or the population standard deviation is known, you would use the z-distribution. Option C would apply if neither distribution is appropriate for the given data.
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