5.Assume that the sample is asimple random sample obtained fromnormala population withadistribution. We have a sample of106 body temperatures having amean of 98.20°F_and a standarddeviation of 0.62°F. Construct a95% confidence interval of thestandard deviation of the bodytemperaturespopulation.fortheentire

Answered: Image /qna-images/answer/79abc069-0ffc-4744-997d-1c075e2b40e7.jpg

Answered: Assume that the sample is a simple…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A random sample of 10 subjects have weights with a standard deviation of 10.9654 kg what is the variance of their weights be sure to include the appropriate units with the result
The distribution of heights of a certain breed of terrier has a mean of 71 centimeters and a standard deviation of 9 centimeters, whereas the distribution of heights of a certain breed of poodle has a mean of 29 centimeters with a standard deviation of 5 centimeters. Assuming that the sample means can be measured to any degree of accuracy, find the probability that the sample mean for a random sample of heights of 64 terriers exceeds the sample mean for a random sample of heights of 100 poodles by at most 44.2 centimeters. What is the probability? Round to four decimals. Use standard normal distribution table.
CNNBC recently reported that the mean annual cost of auto insurance is 973 dollars. Assume the standard deviation is 234 dollars. You take a simple random sample of 61 auto insurance policies. Find the probability that a single randomly selected value is less than 991 dollars.P(X < 991) = Find the probability that a sample of size n=61n=61 is randomly selected with a mean less than 991 dollars.P(M < 991) =
A sample is selected from a population with = 150. After a treatment is administered to the individuals, the sample mean is found to be = 140 and the standard deviation is S= 9. If the sample has n = 18 scores, determine whether the sample is sufficient to conclude that the treatment has significant effect. Use a two tail test with = 0.02.
A researcher collected sample data for 15 middle-aged women. The sample had a mean serum cholesterol level (measured in milligrams per one hundred milliliters) of 192.7, with a standard deviation of 6. Assuming that serum cholesterol levels for middle-aged women are normally distributed, find a 99% confidence interval for the mean serum cholesterol level of all women in this age group. Give the lower limit and upper limit of the 99% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) Lower limit: Upper limit: X Ś
A psychologist obtains a random sample of 20 mothers in the first trimester of their pregnancy. The mothers are asked to play Mozart in the house at least 30 minutes each day until they give birth. After 5 years, the child is administered an 1Q test. It is known that IQs are normally distributed with a mean of 100. If the IQs of the 20 children in the study result in a sample mean of 104.4 and sample standard deviation of 16, is there evidence that the children have higher IQs? Use the a= 0.10 level of significance. Complete parts (a) through (d). (a) Determine the null and alternative hypotheses. Ho: H = 100 Hy: H > 100 (b) Calculate the P-value. P-value = (Round to three decimal places as needed.) %3D Enter your answer in the answer box and then click Check Answer. 2 parts remaining Clear All Check Answer 80 888 112 F7 esc F4 F2 & @ %23 delete 7 8 9 2 3 4 { Q W E Y tab F G H K A D caps lock V B N M C - - .. .- つくC N
An article reports that in a sample of 9 men, the average volume of femoral cartilage (located in the knee) was 18.7 cm3 with a standard deviation of 3.3 cm3 and the average volume in a sample of 9 women was 11.2 cm3 with a standard deviation of 2.4 cm2. Let μXμX represent the population mean for men and let μYμY represent the population mean for women. Find a 95% confidence interval for the difference μX−μYμX−μY . Round down the degrees of freedom to the nearest integer and round the answers to three decimal places. The 95% confidence interval is
A researcher studying the lifespan of a certain species of bacteria. A preliminary sample of 25 bacteria reveals a sample mean of = 70 hours with a standard deviation of s = 7 hours. He would like to estimate the mean lifespan for this species of bacteria to within a margin of error of 0.5 hours at a 99% level of confidence. What sample size should you gather to achieve a 0.5 hour margin of error? He would need to sample bacteria.

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