Assume that the resistance = 3.9 ohms, the width of the rails is 2.2 m, the magnetic field magnitude = 0.3 T, and the speed of the bar is 9.4 m/s instead of the values given in the textbook.
Assume that the resistance = 3.9 ohms, the width of the rails is 2.2 m, the magnetic field magnitude = 0.3 T, and the speed of the bar is 9.4 m/s instead of the values given in the textbook.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Assume that the resistance = 3.9 ohms, the width of the rails is 2.2 m, the magnetic field magnitude = 0.3 T, and the speed of the bar is 9.4 m/s instead of the values given in the textbook.
![**Motional Emf**
The rod shown below moves to the right on essentially zero-resistance rails at a speed of \( v = 3.0 \, \text{m/s} \). If \( B = 0.75 \, \text{T} \) everywhere in the region, what is the current through the \( 5.0 \, \Omega \) resistor? Does the current circulate clockwise or counterclockwise?
**Diagram Explanation:**
- The diagram features a rod moving to the right, indicated by a velocity vector \( \vec{v} \), on horizontal rails.
- The horizontal distance between the rails is labeled as \( 4.0 \, \text{cm} \).
- The magnetic field \( \vec{B} \) is represented by blue dots, indicating that it is directed out of the page.
- A \( 5.0 \, \Omega \) resistor is connected in the circuit formed by the rails and rod.
- The entire setup is connected in such a way that when the rod moves, it induces an electromotive force (emf) due to the magnetic field.
In this context, you are required to calculate the current through the resistor and determine the direction of its circulation (clockwise or counterclockwise) based on the established conditions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb1f0f405-23bc-45b7-8768-1d7e77c63135%2F04623fe9-735f-4143-b228-e307ef39f5a9%2Fwwm12df_processed.png&w=3840&q=75)
Transcribed Image Text:**Motional Emf**
The rod shown below moves to the right on essentially zero-resistance rails at a speed of \( v = 3.0 \, \text{m/s} \). If \( B = 0.75 \, \text{T} \) everywhere in the region, what is the current through the \( 5.0 \, \Omega \) resistor? Does the current circulate clockwise or counterclockwise?
**Diagram Explanation:**
- The diagram features a rod moving to the right, indicated by a velocity vector \( \vec{v} \), on horizontal rails.
- The horizontal distance between the rails is labeled as \( 4.0 \, \text{cm} \).
- The magnetic field \( \vec{B} \) is represented by blue dots, indicating that it is directed out of the page.
- A \( 5.0 \, \Omega \) resistor is connected in the circuit formed by the rails and rod.
- The entire setup is connected in such a way that when the rod moves, it induces an electromotive force (emf) due to the magnetic field.
In this context, you are required to calculate the current through the resistor and determine the direction of its circulation (clockwise or counterclockwise) based on the established conditions.
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