Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. Assume 2.6% of the thermometers are rejected because they have readings that are too high and another 2.6% arerejected because they have readings that are too low. Draw a sketch and find the two readings that are cutoff values separating the rejected thermometers from the others.Click to view page 1 of the table. Click to view page 2 of the table.Which graph represents the region in which thermometers are rejected? Choose the correct graph below.OA.В.OC.D.The cutoff values aredegrees.(Use a comma to separate answers as needed. Round to two decimal places as needed.) NEGATIVE z ScoresPOSITIVE z ScoresStandard Normal (z) Distribution: Cumulative Area from the LEFTStandard Normal (z) Distribution: Cumulative Area from the LEFT.00.0102.03.04.05.06.07.08.09.00.01.02.03.04.05.06.0708.09-3.500.0.5000.5040.5080.5120.5160.5199.5239.5279.5319.5359and0.1.5398.543854785517.5557.55965636.5675.5714.5753lower.00010.2.5793.5832.5871.5910.5948.5987.60266064.6103.6141-3.4.0003.0003.00032000.0003.0003.0003.0003.0003.00020.3.6179,62176255.6293.6331.6368.6406.64436480.6517-3.3.0005.0005.0005.0004.0004.0004.0004.0004.0004.00030.4.6554.6591.6628.6664.6700.6736.6772.6808.6844.6879-3.2.0007.0007.0006.0006.0006.0006.0006.0005.0005.00050.5.6915.6950,69857019.7054.7088,71237157.7190.7224-3.1.0010.0009.0009.0009.0008.0008.0008.0008.0007.00070.6.725772917324735773897422.74547486,7517.7549-3.0.0013.0013.0013.0012.0012.0011.011.001.0010.00100.77580.761176427673.7704.7734.776477947823.7852-2.9.0019.0018.0018.0017.0016.0016.0015.0015.0014.00140.8.78817910793979677995.8023.80518078.8106.8133-2.8.0026.0025.0024.0023.0023.0022.0021.0021.0020.00190.9.8159.8186.8212.8238.8264.8289.8315.8340.8365.8389-2.7.0035.0034.0033.0032.0031.0030.0029.0028.0027.00261.0.8413.843884618485.8508.8531.8554.8577.8599.8621-2.6.0047.0045.0044.0043.0041.0040.0039.0038.0037.00361.1.8643866586868708.87298749.87708790,8810,8830-2.5.0062.0060.0059.0057.0055.0054.0052.0051* 0049.00481.2.8849.88698888.8907.8925.8944.8962.8980.8997.9015-2.4.0082.0080.0078.0075.0073.0071.0069.0068.0066.00641.3.9032.9049.9066.9082.9099.9115.9131.9147.9162.9177-2.3.0107.0104.0102.0099.0096.0094.0091.0089.0087.00841.4.9192.9207.9222.9236.9251.9265.9279.9292.9306.9319-2.2.0139.0136.0132.0129.0125.0122.0119.0116.013.01101.5.9332.93459357.9370.9382.9394.9406.9418.9429.9441-2.1.0179.01740170.0166.0162.0158.0154.0150.0146.01431.6.9452946394749484.9495 •.9505,95159525,9535.9545-2.0.0228.0222.0217.0212.0207.0202.0197.0192.0188.01831.7.9554.9564.9573.9582.9591.9599.9608.9616.9625.9633-1.9.0287.0281.0274.0268.0262.0256.0250.02440239.02331.8.9641.9649,9656.9664.9671.9678.96869693.9699.9706-1.8.0359.0351.0344.0336.0329.0322.0314.0307.0301.02941.9.9713.9719.9726.9732.9738.9744.9750.9756.9761.9767-1.7.0446.0436.0427.0418.0409.0401.0392.0384.0375.03672.0.9772.9778.9783.9788.9793.9798.9803.9808.9812.9817670

Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. Assume 2.6% of the thermometers are rejected because they have readings that are too high and another 2.6% are rejected because they have readings that are too low. Draw a sketch and find the two readings that are cutoff values separating the rejected thermometers from the others. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents the region in which thermometers are rejected? Choose the correct graph below. OA. OB. Oc. OD. The cutoff values are degrees. (Use a comma to separate answers as needed. Round to two decimal places as needed.)