Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading greater than 0.458°C. P(Z > 0.458)
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Q: Assume that the readings on the thermometers are normally distributed with a mean of 0° and…
A: Solution : mean = 0 and SD = 1P( Z < z1 ) = 0.029 and z1 = -1.8957P( Z > z2 ) = 0.029 and z2 =…
Q: Assume that the readings at freezing on a bundle of thermometers are normally distributed with a…
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- Assume the readings on thermometers are normally distributed with a mean of0degreesC and a standard deviation of 1.00degreesC .Find the probability that a randomly selected thermometer reads between negative 2.28 and negative 1.25 and draw a sketch of the region.Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find Pg9, the 69-percentile. This is the temperature reading separating the bottom 69% from the top 31%. P69 = °CAssume that females have pulse rates that are normally distributed with a mean of u=74.0 beats per minute and a standard deviation of o = 12.5 beats per minute. Complete parts (a) through (c) below. a. If 1 adult female is randomly selected, find the probability that her pulse rate is between 70 beats per minute and 78 beats per minute. The probability is. (Round to four decimal places as needed.) Enter your answer in the answer box and then click Check Answer. parts Z remaining Clear All Check Answer 1:29 AM O Type here to search 5/5/2021 144 + 米 IO esc & 7 % %23 3 $ 4. Y %23
- Assume that the mean height of men in the United States is 70 inches, with a standard deviation of 3 inches. A particular man is 80 inches tall. Find the z-score of his height. (Round to two decimal places.)Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. Assume 2.1% of the thermometers are rejected because they have readings that are too high and another 2.1% are rejected because they have readings that are too low. Draw a sketch and find the two readings that are cutoff values separating the rejected thermometers from the others.Suppose the mean cholesterol levels of women age 45-59 is 5.2 mmol/l and the standard deviation is 0.7 mmol/l. Assume that cholesterol levels are normally distributed. Find the probability that a woman age 45-59 has a cholesterol level above 6.1 mmol/l (considered a high level). Round to four decimal places.P(x > 6.1) = Suppose doctors decide to test the woman’s cholesterol level again and average the two values. Find the probability that this woman’s mean cholesterol level for the two tests is above 6.1 mmol/l. Round to four decimal places.P(x̄ > 6.1) = Suppose doctors being very conservative decide to test the woman’s cholesterol level a third time and average the three values. Find the probability that this woman’s mean cholesterol level for the three tests is above 6.1 mmol/l. Round to four decimal places.P(x̄ > 6.1) =
- Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P87, the 87-percentile. This is the temperature reading separating the bottom 87% from the top 13%.P87 = °CAssume that females have pulse rates that are normally distributed with a mean of μ = 76.0 beats per minute and a standard deviation of a = 12.5 beats per minute. Complete parts (a) through (c) below. @ a. If 1 adult female is randomly selected, find the probability that her pulse rate is between 69 beats per minute and 83 beats per minute. The probability is (Round to four decimal places as needed.) b. If 25 adult females are randomly selected, find the probability that they have pulse rates with a mean between 69 beats per minute and 83 beats per minute. W 6 The probability is (Round to four decimal places as needed.) c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30? SA F2 A. Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size. OB. Since the distribution is of sample means, not individuals, the distribution is a normal distribution for any sample…Suppose that the average life of a refrigerator before replacement is μ = 15 years with a (68%of data) range from 13 to 17 years. Let x = age at which a refrigerator is replaced. Assumethat x has a distribution that is approximately normal. Find a good approximation for thestandard deviation of x values.