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Assume that the launching and landing position of the steel ball are at the same height. (y, ye) The mass of the steel ball is 10 g, the initial speed of the ball is 3.80 m/s and the angle at which the ball is released is given as 55". • Mass of the steel ball expressed in SI units Okg/m? Oka Okg'ls Okgts • Initial speed of ball is Om/s Om*s'/s Om/s Ol/m*s a) Which formula do we use to calculate the time of flight? OAt-(vsin(0)/2*g CAt-(2*vsin(0)/g OAt-(vsin(8)/g Oat-(g*v"sin(@))/2

Assume that the launching and landing position of the steel ball are at the same height. (y, ye) The mass of the steel ball is 10 g, the initial speed of the ball is 3.80 m/s and the angle at which the ball is released is given as 55". • Mass of the steel ball expressed in SI units Okg/m? Oka Okg'ls Okgts • Initial speed of ball is Om/s Om*s'/s Om/s Ol/m*s a) Which formula do we use to calculate the time of flight? OAt-(vsin(0)/2*g CAt-(2*vsin(0)/g OAt-(vsin(8)/g Oat-(g*v"sin(@))/2

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Assume that the launching and landing position of the steel ball are at the same height (y,y) The mass of the steel ball is 10 g. the initial speed of the ball is 3.80 m/s and the angle at which the ball is released is given as 55°. • Mass of the steel ball expressed in SI units Okg/m? Okg/s Okgts Oka • Initial speed of ball is: Om/s Om*s'/s Om/s O1/m*s a) Which formula do we use to calculate the time of flight? OAt-(v*sin(0)/2*g CAr-(2*v*sin(e)/g OAt-(vsin(0)/g Oat-(g*v"sin(0)/2.
Transcribed Image Text:Assume that the launching and landing position of the steel ball are at the same height (y,y) The mass of the steel ball is 10 g. the initial speed of the ball is 3.80 m/s and the angle at which the ball is released is given as 55°. • Mass of the steel ball expressed in SI units Okg/m? Okg/s Okgts Oka • Initial speed of ball is: Om/s Om*s'/s Om/s O1/m*s a) Which formula do we use to calculate the time of flight? OAt-(v*sin(0)/2*g CAr-(2*v*sin(e)/g OAt-(vsin(0)/g Oat-(g*v"sin(0)/2.
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