Assume that the ideal op amp in the circuit in the figure is operating in its linear region, Take that R₁ = 45 kn and R₂ = 18 kn. Part A Calculate the power delivered to the R₂. Express your answer with the appropriate units. ANSWER: PR₂ = PR₂ = Part C Find the ratio of the power found in Part A to that found in Part B. ANSWER: 320 mV) PA/PB = Source Part B Calculate the power delivered to the R₂ with the op amp removed from the circuit, that is, with the R₂ resistor connected in the series with the voltage source and the R₁ resistor. Express your answer with the appropriate units. ANSWER: R₂ Load
Assume that the ideal op amp in the circuit in the figure is operating in its linear region, Take that R₁ = 45 kn and R₂ = 18 kn. Part A Calculate the power delivered to the R₂. Express your answer with the appropriate units. ANSWER: PR₂ = PR₂ = Part C Find the ratio of the power found in Part A to that found in Part B. ANSWER: 320 mV) PA/PB = Source Part B Calculate the power delivered to the R₂ with the op amp removed from the circuit, that is, with the R₂ resistor connected in the series with the voltage source and the R₁ resistor. Express your answer with the appropriate units. ANSWER: R₂ Load
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Transcribed Image Text:Assume that the ideal op amp in the circuit in the figure is operating in its linear region, Take that R₁ = 45 k and R₂ = 18 kn.
Part A
Calculate the power delivered to the R₂.
Express your answer with the appropriate units.
ANSWER:
PR₂
Express your answer with the appropriate units.
ANSWER:
PR₂
Part C
Find the ratio of the power found in Part A to that found in Part B.
ANSWER:
320mV
Part B
Calculate the power delivered to the R₂ with the op amp removed from the circuit, that is, with the R₂ resistor connected in the series with the voltage source
and the R₁ resistor.
PA/PB =
+
Source:
Load
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