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Assume that people have the same probability of being born in any given month. Under this assumption, find the probability that in a random group of six people there are at least two with the same birth month. 1. Enter your exact answer as a fraction, not a decimal approximation. You do not have to simplify the fraction. OT 2320704 2985984 2. Convert your answer to a percentage, rounded to the nearest tenth of a percent. You do not need to include the % symbol. 077.72%

Assume that people have the same probability of being born in any given month. Under this assumption, find the probability that in a random group of six people there are at least two with the same birth month. 1. Enter your exact answer as a fraction, not a decimal approximation. You do not have to simplify the fraction. OT 2320704 2985984 2. Convert your answer to a percentage, rounded to the nearest tenth of a percent. You do not need to include the % symbol. 077.72%

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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**Probability of Shared Birth Month Problem** Assume that people have the same probability \(\left(\frac{1}{12}\right)\) of being born in any given month. Under this assumption, find the probability that in a random group of six people, there are at least two with the same birth month. 1. **Exact Fraction Answer:** - Enter your exact answer as a fraction, not a decimal approximation. You do not have to simplify the fraction. - Fraction: \(\frac{2320704}{2985984}\) 2. **Conversion to Percentage:** - Convert your answer to a percentage, rounded to the nearest tenth of a percent. You do not need to include the % symbol. - Percentage: 77.72%
Transcribed Image Text:**Probability of Shared Birth Month Problem** Assume that people have the same probability \(\left(\frac{1}{12}\right)\) of being born in any given month. Under this assumption, find the probability that in a random group of six people, there are at least two with the same birth month. 1. **Exact Fraction Answer:** - Enter your exact answer as a fraction, not a decimal approximation. You do not have to simplify the fraction. - Fraction: \(\frac{2320704}{2985984}\) 2. **Conversion to Percentage:** - Convert your answer to a percentage, rounded to the nearest tenth of a percent. You do not need to include the % symbol. - Percentage: 77.72%
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