Please explain. **Probability of Shared Birth Month Problem**Assume that people have the same probability \(\left(\frac{1}{12}\right)\) of being born in any given month. Under this assumption, find the probability that in a random group of six people, there are at least two with the same birth month.1. **Exact Fraction Answer:** - Enter your exact answer as a fraction, not a decimal approximation. You do not have to simplify the fraction. - Fraction: \(\frac{2320704}{2985984}\)2. **Conversion to Percentage:** - Convert your answer to a percentage, rounded to the nearest tenth of a percent. You do not need to include the % symbol. - Percentage: 77.72%

Answered: Image /qna-images/answer/c2ad433b-9fe5-4013-829a-48935127d881.jpg

Assume that people have the same probability of being born in any given month. Under this assumption, find the probability that in a random group of six people there are at least two with the same birth month. 1. Enter your exact answer as a fraction, not a decimal approximation. You do not have to simplify the fraction. OT 2320704 2985984 2. Convert your answer to a percentage, rounded to the nearest tenth of a percent. You do not need to include the % symbol. 077.72%

Assume that people have the same probability of being born in any given month. Under this assumption, find the probability that in a random group of six people there are at least two with the same birth month. 1. Enter your exact answer as a fraction, not a decimal approximation. You do not have to simplify the fraction. OT 2320704 2985984 2. Convert your answer to a percentage, rounded to the nearest tenth of a percent. You do not need to include the % symbol. 077.72%

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Question

Please explain.

**Probability of Shared Birth Month Problem**

Assume that people have the same probability \(\left(\frac{1}{12}\right)\) of being born in any given month. Under this assumption, find the probability that in a random group of six people, there are at least two with the same birth month.

1. **Exact Fraction Answer:**
- Enter your exact answer as a fraction, not a decimal approximation. You do not have to simplify the fraction.
- Fraction: \(\frac{2320704}{2985984}\)

2. **Conversion to Percentage:**
- Convert your answer to a percentage, rounded to the nearest tenth of a percent. You do not need to include the % symbol.
- Percentage: 77.72%

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