Assume that military aircraft use ejection seats designed for men weighing between 141.2 lb and 202 lb. If women's weights are normally distributed with a mean of 172.6 lb and a standard deviation of 45.9 lb, what percentage of women have weights that are within those limits? Are many women excluded with those specifications? The percentage of women that have weights between those limits is 49.21 %. (Round to two decimal places as needed.) Are many women excluded with those specifications? A. Yes, the percentage of women who are excluded, which is the complement of the probability found previously, shows that about half of women are excluded. B. Yes, the percentage of women who are excluded, which is equal to the probability found previously, shows that about half of women are excluded. C. No, the percentage of women who are excluded, which is the complement of the probability found previously, shows that very few women are excluded. D. No, the percentage of women who are excluded, which is equal to the probability found previously, shows that very few women are excluded. 9:18 1 ME = 172.6, TF=45.9 F→ Female; =P/ 141-2-172.6 X-ME < 202-172-6 :45-9 (या P(-0.6841 < z <0.6405) P(Z

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
icon
Related questions
Topic Video
Question

I am not sure how this response has been obtained? Can you help me? Can you go step-by-step, essentially as though you are doing an introduction, please? Because, I feel so lost. Someone tried to explain it in the second picture, but I cannot interpret it, as I need rationale to go with answers, not merely the answer. 

In advance, I sincerely appreciate your efforts.

Assume that military aircraft use ejection seats designed for men weighing between 141.2 lb and 202 lb. If women's weights are normally distributed with a mean of 172.6 lb and a standard deviation of 45.9 lb, what
percentage of women have weights that are within those limits? Are many women excluded with those specifications?
The percentage of women that have weights between those limits is 49.21 %.
(Round to two decimal places as needed.)
Are many women excluded with those specifications?
A. Yes, the percentage of women who are excluded, which is the complement of the probability found previously, shows that about half of women are excluded.
B. Yes, the percentage of women who are excluded, which is equal to the probability found previously, shows that about half of women are excluded.
C. No, the percentage of women who are excluded, which is the complement of the probability found previously, shows that very few women are excluded.
D. No, the percentage of women who are excluded, which is equal to the probability found previously, shows that very few women are excluded.
Transcribed Image Text:Assume that military aircraft use ejection seats designed for men weighing between 141.2 lb and 202 lb. If women's weights are normally distributed with a mean of 172.6 lb and a standard deviation of 45.9 lb, what percentage of women have weights that are within those limits? Are many women excluded with those specifications? The percentage of women that have weights between those limits is 49.21 %. (Round to two decimal places as needed.) Are many women excluded with those specifications? A. Yes, the percentage of women who are excluded, which is the complement of the probability found previously, shows that about half of women are excluded. B. Yes, the percentage of women who are excluded, which is equal to the probability found previously, shows that about half of women are excluded. C. No, the percentage of women who are excluded, which is the complement of the probability found previously, shows that very few women are excluded. D. No, the percentage of women who are excluded, which is equal to the probability found previously, shows that very few women are excluded.
9:18 1
ME = 172.6, TF=45.9
F→ Female;
=P/ 141-2-172.6 X-ME < 202-172-6
:45-9
(या
P(-0.6841 < z <0.6405)
P(Z<O:6405) -P(ZE =O.684))
%3D
6.7391-O•2470
0.4921
49.21%0
as
100-49.2| = 50.79 %,
excluded with those specificationy
so, optiom A|.
blease Rate!!
any doubts please ask ! thank you :))
Transcribed Image Text:9:18 1 ME = 172.6, TF=45.9 F→ Female; =P/ 141-2-172.6 X-ME < 202-172-6 :45-9 (या P(-0.6841 < z <0.6405) P(Z<O:6405) -P(ZE =O.684)) %3D 6.7391-O•2470 0.4921 49.21%0 as 100-49.2| = 50.79 %, excluded with those specificationy so, optiom A|. blease Rate!! any doubts please ask ! thank you :))
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Propositional Calculus
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman