Assume that a system's memory has 128M bytes. Blocks are 64 bytes in length, and the cache consists of 32K blocks. Show the format for a main memory address assuming a 2-way setassociative cache mapping scheme and byte addressing. Be sure to include the fields as well as their sizes
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Q: Assume that a system's memory has 128M bytes. Blocks are 64 bytes in length, and the cache consists…
A: The memory has 128M words = 27M = 27.220 = 27+20 = 227words. Hence it needs 27 bits for address…
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A: Note - As per the guidelines, we are only allowed to answer 1 question with 3 sub-parts a time.…
Q: Assume that we have a computer with a cache memory of 512 blocks with a total size of 128K bits.…
A: Given the cache's capacity of 128K bits. Cache capacity in bytes = 128K bits / 8 = 16KB Because this…
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A: Below is the answer with explanation and calculation:
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Q: Question: A computer system contains a main memory of 32KB. It also has a 1KB cache divided into…
A: The answer given below:-
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- Suppose a byte-addressable computer using set associative cache has 224 bytes of main memory and a cache size of 64K bytes, and each cache block contains 32 bytes. a) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache, that is, what are the sizes of the tag, set, and offset fields? b) If this cache is 4-way set associative, what is the format of a memory address as seen by the cache?Suppose a byte-addressable computer using set associative cache has 8M byes of main memory and a cache of 128 blocks, where each cache block contains 64 bytes. a) If this cache is 4-way set associative, what is the format of a memory address as seen by the cache, that is, what are the sizes of the tag, set, and offset fields? b) If this cache is 16-way set associative, what is the format of a memory address as seen by the cacheSuppose a byte-addressable computer using set associative cache has 216 bytes of main memory and a cache of 32 blocks, and each cache block contains 8 bytes. a) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache, that is, what are the sizes of the tag, set, and offset fields? b) If this cache is 4-way set associative, what is the format of a memory address as seen by the cache?
- Suppose a byte-addressable computer using set associative cache has 4Mbyes of main memory and a cache of 64 blocks, where each cache block contains 8 bytes. a) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache, that is, what are the sizes of the tag, set, and offset fields? b) If this cache is 4-way set associative, what is the format of a memory address as seen by the cache? Show all work and explain how you got the answers please. Thanks5. Suppose a byte-addressable computer using set-associate cache has 2^21 bytes of main memory and a cache of 64 blocks, where each cache block contains 16 bytes. a) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache; that is, what are the sizes of the tag, set, and offset fields? b) If this cache is 4-way set associative, what is the format of a memory address as seen by the cache; that is, what are the sizes of the tag, set, and offset fields?A cache memory system with capacity of N words and block size of B words is to be designed. If it is designed as a direct mapped cache, the length of the TAG field is 14 bits. If it is designed as a 4-way set associative cache, the length of the TAG field will be ………… bits.
- By convention, a cache is named according to the amount of data it contains (ie., a 4 KiB cache can hold 4 KiB of data); however, caches also require SRAM to store metadata such as tags and valid bits. For this exercise, you will examine how a cache's configuration affects the total amount of SRAM needed to implement it as well as the performance of the cache. For all parts, assume that the caches are byte addressable, and that addresses and words are 64 bits. 1. Calculate the total number of bits required to implement a 32 KiB cache with two-word blocks. 2. Calculate the total number of bits required to implement a 64 KiB cache with 16-word blocks. How much bigger is this cache than the 32 KiB cache described in Exercise (1) above? (Notice that, by changing the block size, we doubled the amount of data without doubling the total size of the cache.) 3. Explain why this 64 KiB cache, despite its larger data size, might provide slower performance than the first cache. 4. Generate a…By convention, a cache is named according to the amount of data it contains (i.e., a 4 KiB cache can hold 4 KiB of data); however, caches also require SRAM to store metadata such as tags and valid bits. For this exercise, you will examine how a cache's configuration affects the total amount of SRAM needed to implement it as well as the performance of the cache. For all parts, assume that the caches are byte addressable, and that addresses and words are 64 bits. (a) Calculate the total number of bits required to implement a 32 KiB cache with two-word blocks. (b) Calculate the total number of bits required to implement a 64 KiB cache with 16-word blocks. How much bigger is this cache than the 32 KiB cache described in Part a? (Notice that, by changing the block size, we doubled the amount of data without doubling the total size of the cache.)Suppose a byte-addressable computer using set-associative cache has 216 bytes of main memory and a cache of 32 blocks, and each cache block contains 8 bytes.Q.) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache; that is, what are the sizes of the tag, set, and offset fields?
- A cache memory has a line size of eight 64-bit words and a capacity of 4K words. The main memory size that is cacheable is 1024 Mbits. Assuming 4-way set associative mapping and that the addressing is done at the byte level. What is the format of the main memory addresses (i.e s-d, d, and w)? For the hexadecimal main memory location 2BFACEDH, find the corresponding 4-way set-associative memory formatIn general, a cache is named according to the amount of data it contains (i.e., a 4 KiB cache can hold 4 KiB of data); however, caches also require SRAM to store metadata such as tags and valid bits. You design this cache memory and will examine how a cache's configuration affects the total amount of SRAM needed to implement it as well as the performance of the cache. For all parts, assume that the that addresses and words are 64 bits. (A) Calculate the total number of bits required to implement a 32 KiB cache with two-word blocks. (B) Calculate the total number of bits required to implement a 96 KiB cache with 16-word blocks. How much bigger is this cache than the 32 KiB cache described in (A) above? (Notice that, by changing the block size, we increased the amount of data without doubling the total size of the cache.) (C) Explain why this 96 KiB cache, despite its larger data size, might provide slower performance than the first cache.In general, a cache is named according to the amount of data it contains (i.e., a 4 KİB cache can hold 4 KiB of data); however, caches also require SRAM to store metadata such as tags and valid bits. You design this cache memory and will examine how a cache's configuration affects the total amount of SRAM needed to implement it as well as the performance of the cache. For all parts, assume that the that addresses and words are 64 bits. (A) Calculate the total number of bits required to implement a 32 KİB cache with two-word blocks. (B) Calculate the total number of bits required to implement a 96 KiB cache with 16-word blocks. How much bigger is thi cache than the 32 KiB cache described in (A) above? (Notice that, by changing the block size, we increased the amount of data without doubling the total size of the cache.) (C) Explain why this 96 KiB cache, despite its larger data size, might provide slower performance than the first cache.