Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E.that corresponds to a sample of size 268 with 20.9% successes at a confidence level of 99%.М.Е. %3%Answer should be obtained without any preliminary rounding. However, the critical value may berounded to 3 decimal places. Round final answer to one decimal place

From the given information, The sample size is 268. Proportion=p^=20.9%=0.209 Confidence level is…

Answered: Assume that a sample is used to…

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.3: Measures Of Spread

Problem 1GP

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2) In a random sample 765 adults in Jordan, 322 say they could not cover a 300 JD unexpected expense without borrowing money or going into debt. What population is under consideration in the data set? b. What parameter is being estimated? What is the point estimate for the parameter? d. What is the name of the statistic can we use to measure the uncertainty of the point а. с. estimate? e. Compute the value from part (d) for this context. f. A news analyst thinks the value is actually 50%. Should the news analyst be surprised by the data? g. Suppose the true population value was found to be 40%. If we use this proportion to recompute the value in part (e) using p = 0.4 instead of p, does the resulting value change much?
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An IQ test is designed so that the mean is 100 and the standard deviation is 24 for the population of normal adults. Find the sample size necessary to estimate the mean IQ score of statistics students such that it can be said with 95% confidence that the sample mean is within 5 IQ points of the true mean. Assume that Ơ = 24 and determine the required sample size using technology. Then determine if this is a reasonable sample size for a real world calculation.
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Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E. that corresponds to a sample of size 268 with 20.9% successes at a confidence level of 99%. M.E. =