Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E. that corresponds to a sample of size 96 with 41.7% successes at a confidence level of 99%. M.E.= Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places. Round final answer to one decimal place

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**Estimating Population Proportion and Margin of Error**

In this example, a sample is used to estimate a population proportion \( p \). The objective is to determine the margin of error (M.E.) for a sample of size 96 with a success rate of 41.7% and a confidence level of 99%.

**Problem Statement:**

Assume that a sample is used to estimate a population proportion \( p \). Find the margin of error \( M.E. \) that corresponds to a sample of size 96 with 41.7% successes at a confidence level of 99%.

\( M.E. = \_\_\_\_\% \)

*Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places. Round the final answer to one decimal place.*

This exercise involves understanding how to calculate the margin of error in proportion samples by applying statistical methods, particularly focusing on a high confidence level of 99%.
Transcribed Image Text:**Estimating Population Proportion and Margin of Error** In this example, a sample is used to estimate a population proportion \( p \). The objective is to determine the margin of error (M.E.) for a sample of size 96 with a success rate of 41.7% and a confidence level of 99%. **Problem Statement:** Assume that a sample is used to estimate a population proportion \( p \). Find the margin of error \( M.E. \) that corresponds to a sample of size 96 with 41.7% successes at a confidence level of 99%. \( M.E. = \_\_\_\_\% \) *Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places. Round the final answer to one decimal place.* This exercise involves understanding how to calculate the margin of error in proportion samples by applying statistical methods, particularly focusing on a high confidence level of 99%.
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