Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval for a sample of size 388 with 171 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. 95% C.I. =
Q: Assume that population proportion is to be estimated from the sample described. Use the sample…
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Q: e: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the…
A: Sample size n =47 Sample mean=109 Population standard deviation =32
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A: Solution: From the given information, confidence level is 0.95, σ=315 and E=105.
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A: given data n = 31σ2 = 15∴σ = 15 = 3.873x¯ = 5695% ci for μ = ?
Q: d. FIND t a n = 10 for the 90% confidence interval for the mean. %3D
A: d. Given: n=10 α=0.1 The degrees of freedom is obtained as below: df=n-1=10-1=9 Critical value: The…
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Q: Assume that a sample is used to estimate a population proportion p. Find the 90% confidence interval…
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Q: Find z, for the 84% confidence interval for the population mean. O a. 0.7955 O b. 1.44 O c. None O…
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Q: poofy Marketing Solutions conducted a survey among 16 randomly selected visitors p the newly opened…
A: Solution: Given information: n= 16 Sample size Degree of freedom =n-1= 15 x= 67 Sample means =…
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A: Given,Margin of error, E = 0.10Population standard deviation, σ = 0.85Confidence level, C = 99% =…
Q: Assume that a samlpe is used to estimate a population proportion p. Find the margin of error E that…
A: Given that n=sample size=800p=probability of success=40%=0.40z= critical value for 98% confidence…
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Q: A. Find the confidence intervals for the population mean from the given data. 1. x = 5.8, n = 36, o…
A: as per Bartleby guideline expert have to answer first question only dear students please upload…
Q: Assume that a sample is used to estimate a population p. Find the margin of error M.E. that…
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Q: A statistics practitioner took a random sample of 56 observations from a population whose standard…
A: We have given that, Sample size (n) = 56, population standard deviation (σ) = 35 and sample mean…
Q: Assume that a sample is used to estimate a population proportion p. Find the 90% confidence interval…
A: It is given that sample size (n) is 288 and p-hat value is 0.389.
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A: Margin of error (E) for proportion is defined as below E = Width2…
Q: Assume that population mean is to be estimated from the sample described. Use the sample results to…
A: Given95% confidence interval N=361 x = 59.1 seconds. z= 4.9 SecondsFind the margin of error?
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A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…
Q: Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval…
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Q: The estimated prevalence is 11%, and the desired confidence level is 91% with a margin of error of…
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Q: Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval…
A: Solution-: Given: n=130, x=73, c=0.98 Our aim to find 98% C.I. for the population proportion.
Q: city. Construct a 99% confidence interval estimate of the mean amount of mercury in the population.…
A: From the provided information, Sample size (n) = 7 Confidence level = 99% Level of significance = 1…
Q: assume that a sample is used to estimate a population proportion p. find the margin of error that…
A: Givensample size(n)=325x=54.2p^=xn=54.2325=0.1668confidence level = 95%
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A: Step-by-step procedure to obtain the 98% confidence interval for them mean of the population using…
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A: Level of significance ɑ=0.25
Q: A statistics practitioner took a random sample of 43 Note: For each confidence interval, enter your…
A: n = 43 standard deviation = 27 mean = 104 95% confidence interval for mean is given by x±zα2*σn 104…
Q: atistics practitioner took a random sample of 49 observations from a population whose standard…
A: Sample size n =49 Sample mean=103 Population standard deviation =25
Q: Lower %3D
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Q: Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval…
A: Given data,n=258x=115Find the 95% confidence interval
Q: Suppose you calculate a 95% confidence interval for a proportion to to be: 0.39 to 0.78. Determine…
A: Given, Lower bound = 0.39 Upper bound = 0.78 Here, we use to determine the margin of error.
Q: Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E.…
A: Solution: Given information: n= 220 Sample size x= 110 successes p^=xn=110220= 0.5 Sample…
Q: assume that a sample is used to estimate a population proportion p. find the margin of error E that…
A: The confidence level is 0.02.
Q: Assume that a sample is used to estimate a population proportion p. Find the margin of error E that…
A: The question is about confidence interval.Given :No. of selected observations ( n ) = 1400Sample…
Q: /hat is the 95% confidence interval for this sample mean? to 82.0 to 67.4 to 82.9 to 67.6
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A: We have find distribution...
Q: Assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval…
A: Given data The sample size is n=300. The number of successes is x=189. The confidence level is…
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A: Given Data Lower limit,LL = 12.5 upper limit,UL = 18.5
Q: 20. Suppose a 90% confidence interval is stated as (0.3011, 0.4189). What is the sample proportion…
A: The given 90% confidence interval for population proportion is, (0.3011, 0.4189) The upper limit is,…
Q: Assume that a sample is used to estimate a population proportion p. Find the 90% confidence interval…
A: A random sample of size 293 with 103 successes; n=293 x=103 α=0.10
Q: A statistics practitioner took a random sample of 59 observations from a population whose standard…
A: sample size(n)=59 Population standard deviation(σ)=32 Mean(x)=95
Q: Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval…
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Q: You sample 36 students to find out how many hours they spent online last week. Your sample mean is…
A: From the provided information, Sample size (n) = 36 Sample mean (x̅) = 54 Population standard…
Q: Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval…
A: It is given that, 88% of the 210 samples lead to success. Thus, the sample size n = 210 and the…
Q: A statistics practitioner took a random sample of 43 observations from a population whose standard…
A: We have given that, sample mean (x̄) = 109, standard deviation (σ) = 30 and sample size (n) = 43
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A: Confidence interval=(0.729,0.755) Find margin of error=E
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- Assume that a sample is used to estimate a population proportion p. Find the 99.5% confidence interval for a sample of size 324 with 230 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. 99.5% C.I. =It is desired to estimate the proportion of cannabis users at a university. What is the sample size required to if we wish to have a 95% confidence in the interval and an error of 10%? 385 68 10 97Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
- Find the value:Assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval for a sample of size 392 with 102 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. 80% C.I. =Use the given confidence interval to find the margin of error and the sample proportion. (0.740,0.766) E=enter your response here (Type an integer or a decimal.)
- A statistics practitioner took a random sample of 42 observations from a population whose standard deviation is 30 and computed the sample mean to be 102. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 90% confidence. Confidence Interval = C. Estimate the population mean with 99% confidence. Confidence Interval =A random sample of 12 cats was collected to study the lifespan with the data listed below. Find the 87% confidence interval for the population mean. Round all values to two decimals. 13, 15, 18, 16, 8, 12, 13, 15, 8, 13, 12, 11. Provide your answer below.assume that a sample is used to estimate a population proportion p. find the margin of error E that corresponds to the given statistics and confidence level. 98% confidence; the sample size is 730, of which 30% are successes
- The accompanying table shows data for the weights of backpacks for men and women. Assume that the data are from random samples and the distributions are Normal. Complete parts (a) and (b) below. E Click the icon to view the data table. a. Find a 95% confidence interval for the difference between means HFemale - HMale state whether it captures 0, and explain what that shows about the mean. The 95% confidence interval is ( D (Round to two decimal places as needed. Use ascending order.) Backpack weights Female Male 10 10 12 8 9. 7 5 10 7 20 3 11 8 14 13 11 14 6 7 22 11 12 15 10 17 22 10 7 25 11 7 15 11 11 4 16 13 20 21 15 10 9. 16 10 15 13 10 10 17 12 11 38 6. 6. 7 19 12 13 20 8 14 15 18 19 10 16 16 13 18 12 14 13 13 15 14 14 7 7 14 13 27 11The ?z value for a 96.6% confidence interval estimate is A. 1.96 B. 2.00 C. 2.12 D. 1.82Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96