Assume that a sample is used to estimate a population mean u. Find the 99% confidence interval for a sample of size 977 with a mean of 16.6 and a standard deviation of 15.6. Enter your answer as a tri-linear inequality accurate to one decimal place (because the sample statistics are reported accurate to one decimal place). < µ < Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.

MATLAB: An Introduction with Applications
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Chapter1: Starting With Matlab
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**Example Problem: Estimating a Population Mean**

Assume that a sample is used to estimate a population mean \( \mu \). Find the 99% confidence interval for a sample of size 977 with a mean of 16.6 and a standard deviation of 15.6. Enter your answer as a tri-linear inequality accurate to one decimal place (because the sample statistics are reported accurate to one decimal place).

\[ \text{[  ]} < \mu < \text{[  ]} \]

**Instructions:**

- Answer should be obtained without any preliminary rounding. 
- However, the critical value may be rounded to 3 decimal places.

**Explanation:**

This problem involves calculating a confidence interval for a population mean from sample data. The interval provides a range of values within which the true population mean is likely to fall. This calculation assumes that the distribution of the sample mean is approximately normal due to the large sample size (Central Limit Theorem). 

To solve this, you will need to:

1. Determine the critical value for a 99% confidence level.
2. Calculate the standard error of the mean.
3. Apply the formula for the confidence interval:

\[
\text{Confidence Interval} = \text{mean} \pm (\text{critical value} \times \text{standard error})
\]

Where:
- **Mean** = 16.6
- **Standard Deviation** = 15.6
- **Sample Size** = 977

Ensure all calculations maintain accuracy until the final answer, where the result will be rounded to one decimal place for reporting.
Transcribed Image Text:**Example Problem: Estimating a Population Mean** Assume that a sample is used to estimate a population mean \( \mu \). Find the 99% confidence interval for a sample of size 977 with a mean of 16.6 and a standard deviation of 15.6. Enter your answer as a tri-linear inequality accurate to one decimal place (because the sample statistics are reported accurate to one decimal place). \[ \text{[ ]} < \mu < \text{[ ]} \] **Instructions:** - Answer should be obtained without any preliminary rounding. - However, the critical value may be rounded to 3 decimal places. **Explanation:** This problem involves calculating a confidence interval for a population mean from sample data. The interval provides a range of values within which the true population mean is likely to fall. This calculation assumes that the distribution of the sample mean is approximately normal due to the large sample size (Central Limit Theorem). To solve this, you will need to: 1. Determine the critical value for a 99% confidence level. 2. Calculate the standard error of the mean. 3. Apply the formula for the confidence interval: \[ \text{Confidence Interval} = \text{mean} \pm (\text{critical value} \times \text{standard error}) \] Where: - **Mean** = 16.6 - **Standard Deviation** = 15.6 - **Sample Size** = 977 Ensure all calculations maintain accuracy until the final answer, where the result will be rounded to one decimal place for reporting.
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