Assume that a procedure yields a binomial distribution with 1210 trials and the probability of success for one trial is p = 75%. n = : Find the mean for this binomial distribution. (Round answer to one decimal place.) μ = Find the standard deviation for this distribution. (Round answer to two decimal places.) Use the range rule of thumb to find the minimum usual value μ-20 and the maximum usual value μ+20. Enter answer as an interval using square-brackets only with whole numbers. usual values =

MATLAB: An Introduction with Applications
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Assume that a procedure yields a binomial distribution with
n = 1210 trials and the probability of success for one trial is
P = 75%.
р
Find the mean for this binomial distribution.
(Round answer to one decimal place.)
μl
=
Find the standard deviation for this distribution.
(Round answer to two decimal places.)
O =
Use the range rule of thumb to find the minimum usual value
µ-20 and the maximum usual value µ+2o.
Enter answer as an interval using square-brackets only with
whole numbers.
usual values
=
Transcribed Image Text:Assume that a procedure yields a binomial distribution with n = 1210 trials and the probability of success for one trial is P = 75%. р Find the mean for this binomial distribution. (Round answer to one decimal place.) μl = Find the standard deviation for this distribution. (Round answer to two decimal places.) O = Use the range rule of thumb to find the minimum usual value µ-20 and the maximum usual value µ+2o. Enter answer as an interval using square-brackets only with whole numbers. usual values =
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Step 1: Given information

Assume that a procedure yields a binomial distribution with n equals 1210 trials and 

The probability of success for one trial is p equals 0.75.

i.e. X tilde B open parentheses n equals 1210 comma space p equals 0.75 close parentheses

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