Assume that 15%. of people are left- nanded. If 6 people are selected at random. a. Find the probability that there are exactly 3. lefties the group. A b. Find Re nt inf acr the probability that there are 5 lefties in the group. Dat D C. Find the probability that there are group no more than 2 lefties in the least

Q: held

A: 1. Existence of a virtual smooth controller \(y^* = a(z)\) that stabilizes the \(z\) dynamics…

Q: Selve du 4824 8.

A: Given heat equation, ∂u∂t=4∂2u ∂x2u(0,t)=0u(8,t)=0u(x,0)=4x-12x2=f(x,y)  Here length l=8 and c2=4

Q: 61.6(2.1/3)

A: Given, 61.6(2.1/3)

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A: Given : ∫132x5dx

Q: 3. 27648– 5358

A: See the attachment

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A: In figure,

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A:

Q: 0.3(7 + 2x) + 1.3x = 3.5

A:

Q: 5475

A: Simplification

Q: 8. 5 912

A:

Q: 1 -de 17 Vīo O vỹ O o o O

A:

Q: 32/2,625

A:

Q: 4. X = 100

A:

Q: 2'dr

A: Explanation and solution is given below....

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A: Given: 16.2

Q: V300

A:

Q: {A €R?x2 | tr(A) = 0} | tr(A) — 0}

A: Here we take a general matrix of the given set then find the basis.

Q: B. 264

A:

Q: 51. 2 In 2 -

A: From the data:

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A: Refer to the question we have to evaluate the LCM of 5 and 2,

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A: The given equations are, 6.80+0.90x=y          ...17.30+0.65x=y          ...2 Substitute the value…

Q: 7. 185 X 24

A: Solution To find the multiplication we use the following rule .

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A: Addition of the given numbers  90.8 +178 = 268.

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A: We have to explain about the given formula: V=43π r3 We know that this is the formula of volume for…

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Q: 214 8.

A:

Q: tani o

A: Trigonometry

Q: Full soln

A: Approach to solving the question:Please see attached photos for detailed solutions. Thank…

Q: 15 V =-

A: To find  I = ∫0915xdx

Q: 2.73-0.94

A: Here we subtract a number in another number.

Q: 1. 24325- 1345 2. 32547- 2567 27648- 5358 3.

A:

Q: 14.05 X 7 5.

A:

Q: 60 yd 47 yd О 47 52 55 58

A:

Q: 5x + 8 = 78

A: We Solve the Equation, Find The value of x.  Given Equation is 5x+8= 78.

Q: 2 5" 3 + 5.

A:

Q: 60 30 6./3

A:

Q: 5,239 + 2,794=

A: see below the answer here nothing to explain it

Q: 2sinx +-cafx costX

A: We know that sin^2x+cos^2x=1 2sin^2x+1-cos^2x\cos^2x = 2sin^2x+sin^2x/cos^2x 3sin^2x/cos^2x = tan^2x