Assume patm = 1.00 atm....what is the gas pressure pgas?   express answer in pascals to three sig figures...

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Assume patm = 1.00 atm....what is the gas pressure pgas?

 

express answer in pascals to three sig figures...

Learning Goal:
To practice Tactics Box 14.1 Hydrostatics.
In problems about liquids in hydrostatic equilibrium, you
often need to find the pressure at some point in the liquid.
This Tactics Box outlines a set of rules for thinking about
such hydrostatic problems.
Figure
Peas
A
EU.
B
h₂
mercury
1 of 1
Transcribed Image Text:Learning Goal: To practice Tactics Box 14.1 Hydrostatics. In problems about liquids in hydrostatic equilibrium, you often need to find the pressure at some point in the liquid. This Tactics Box outlines a set of rules for thinking about such hydrostatic problems. Figure Peas A EU. B h₂ mercury 1 of 1
TACTICS BOX 14.1 Hydrostatics
1. Draw a picture. Show open surfaces, pistons, boundaries, and other features that affect the pressure. Include height and area
measurements and fluid densities. Identify the points at which you need to find the pressure. These objects make up the system;
the environment is everything else.
2. Determine the pressure at the various surfaces.
• For a surface open to the air, po = Patm, usually 1 atm.
• For a surface covered by a gas, po = Pgas.
• For a closed surface, p = F/A, where F is the force the surface, such as a piston, exerts on the fluid and A is the
area of the surface.
3. Use horizontal lines. Pressure in a connected fluid is the same at any point along a horizontal line.
4. Allow for gauge pressure. Pressure gauges read pg = p − 1 atm.
5. Use the hydrostatic pressure equation: p = po + pgh, where p is the density of the fluid, g is the free-fall acceleration, and ʼn is
the height of the fluid.
The
these rules to work out the following problem: A U-shaped is connected to box at one end and open to the air at the
box is full of gas at pressure pgas, and the tube is filled with mercury of density 1.36×104 kg/m³ . When the liquid in the tube reaches static
equilibrium, the mercury column is h₁ = 10.0 cm high in the left arm and h₂ = 6.00 cm high in the right arm, as shown in the figure. (Figure 1)
What is the gas pressure pgas inside the box?
Part A
Find the pressures PÅ and på at surfaces A and B in the tube, respectively.
PA, PB =
O Pgas + Patm, Patm
Pgas, Patm
Patm, Patm
Pgas, Pgas
O Pgas, Pgas + Patm
Transcribed Image Text:TACTICS BOX 14.1 Hydrostatics 1. Draw a picture. Show open surfaces, pistons, boundaries, and other features that affect the pressure. Include height and area measurements and fluid densities. Identify the points at which you need to find the pressure. These objects make up the system; the environment is everything else. 2. Determine the pressure at the various surfaces. • For a surface open to the air, po = Patm, usually 1 atm. • For a surface covered by a gas, po = Pgas. • For a closed surface, p = F/A, where F is the force the surface, such as a piston, exerts on the fluid and A is the area of the surface. 3. Use horizontal lines. Pressure in a connected fluid is the same at any point along a horizontal line. 4. Allow for gauge pressure. Pressure gauges read pg = p − 1 atm. 5. Use the hydrostatic pressure equation: p = po + pgh, where p is the density of the fluid, g is the free-fall acceleration, and ʼn is the height of the fluid. The these rules to work out the following problem: A U-shaped is connected to box at one end and open to the air at the box is full of gas at pressure pgas, and the tube is filled with mercury of density 1.36×104 kg/m³ . When the liquid in the tube reaches static equilibrium, the mercury column is h₁ = 10.0 cm high in the left arm and h₂ = 6.00 cm high in the right arm, as shown in the figure. (Figure 1) What is the gas pressure pgas inside the box? Part A Find the pressures PÅ and på at surfaces A and B in the tube, respectively. PA, PB = O Pgas + Patm, Patm Pgas, Patm Patm, Patm Pgas, Pgas O Pgas, Pgas + Patm
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