Oil 750 kPa SG= 0.72 75cm Air Water Mercury SG= 13.6 30 cm Figure 1 Je

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Oil
750 kPa
SG= 0.72
75cm
Air
Water
.Mercury
SG= 13.6
30 cm
Figure 1
Transcribed Image Text:Oil 750 kPa SG= 0.72 75cm Air Water .Mercury SG= 13.6 30 cm Figure 1
The gage pressure of the air in the tank shown in Figure 1 is measured to be 750KP.. Determine the
differential height h of the mercury column.
Transcribed Image Text:The gage pressure of the air in the tank shown in Figure 1 is measured to be 750KP.. Determine the differential height h of the mercury column.
Expert Solution
Step 1

Given:

The Gauge pressure at the tank is P = 750 kPa

The height of the water column is hw = 30 cm

The density of the water is ρw = 1000 kg/m3

The height of the oil column is ho = 75 cm

The specific gravity of mercury is γm = 13.6

The specific gravity of oil is γo = 0.72

 

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