The task is to design a synthesis of the product from the given starting material using two steps. Only the major product from each step is considered for the next phase. Reagents should be used in one equivalent, and an appropriate workup is assumed after each step unless specified otherwise.**Chemical Structures:**- **Starting Material:** Cyclopentanol with an OH group attached to a secondary carbon.- **Product:** A cyclopentane structure with an azide (N₃) group replacing the OH group, maintaining stereochemistry.**Reagent Options:**1. **HBr (no workup)**2. **NaN₃, DMF**3. **TsCl, pyridine**4. **H₂O, H₂SO₄ (mild)**5. **2 equiv HN₃, DMF**6. **PBr₃ (no workup)**7. **NaBr, acetone****Procedure:**- **Synthesis Step 1:** Choose the appropriate reagent from the dropdown menu.- **Synthesis Step 2:** Choose the next reagent to convert the intermediate to the final product.Following these steps will ensure the conversion of the starting material to the desired product. The exercise involves designing a synthesis of a product from a given starting material using a dropdown menu. The synthesis involves two steps, and only the expected major product is considered. Assume one equivalent of reagents and an appropriate workup after each step, unless otherwise specified.**Starting Material:** - An alkene structure is shown as the starting material.**Product:** - The product is identified as having an azide (N₃) functional group bound to a cyclopentane ring.**Options for Synthesis Steps:** You choose from the following reagent options for the two-step synthesis:1. HBr (no workup)2. PBr₃ (no workup)3. TsCl, pyridine4. H₂O, H₂SO₄ (mild)5. NaN₃6. HBr, ROOR7. NaBr, acetone**Synthesis Step 1:**- Dropdown menu to select the reagent for the first step.**Synthesis Step 2:**- Dropdown menu to select the reagent for the second step.Your task is to choose the appropriate reagents for each step to convert the starting material into the desired product.

Substitution reactions are the chemical reactions that involve replacement of one group by other.…

Assume one equivalent of reagents and appropriate workup after each step, unless otherwise indicated. OH N3 Step 1? Step 2 ? Starting Material Product 1. HBr (no workup) 2. NaN3, DMF 3. TsCl, pyridine 4. H20, H2SO4 (mild) 5. 2 equiv HN3, DMF 6. PBr3 (no workup) 7. NaBr, acetone Synthesis Step 1 choose your answer... V Synthesis Step 2 choose your answer...

Assume one equivalent of reagents and appropriate workup after each step, unless otherwise indicated. OH N3 Step 1? Step 2 ? Starting Material Product 1. HBr (no workup) 2. NaN3, DMF 3. TsCl, pyridine 4. H20, H2SO4 (mild) 5. 2 equiv HN3, DMF 6. PBr3 (no workup) 7. NaBr, acetone Synthesis Step 1 choose your answer... V Synthesis Step 2 choose your answer...

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Three white wine brands, D, M, and B were tested for tartaric acid (FW=150.09) content. Tartaric acid has two acidic hydrogens. The allowable tartaric acid content in wine is in between 0.5 g to 10 g per liter. The wine is considered to be unstable with too much tartaric acid and content. However, since the bottle storing NaOH was left ajar for over two weeks, this was standardized again with KHP (FW=204.22) thrice with the following masses of KHP and their respective volumes, shown in the table 1. Table 1. Trial 1 Trial 2 Trial 3 W (KHP), mg 200.0 198.5 187.6 V (NaOH), mL 20.00 18.20 19.40 C (NaOH), M ? ? ? Preparation of the wine sample: 50.00 mL of each wine (d=1.75 g/mL) was diluted to 250.0 mL with water and a 50.00 mL aliquot was titrated with the NaOH, with results in table 2. Table 2. D M B V (NaOH), mL 20.00 18.20 19.40 W (Tartaric acid), mg ? ? ? Answer the following: In which trial…
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