↓ Assume each newborn baby has a probability of approximately 0.52 of being female and 0.48 of being male. For a family with four children, let X = number of children who are girls. a. Identify the three conditions that must be satisfied for X to have the binomial distribution. b. Identify n and p for the binomial distribution. c. Find the probability that the family has two girls and two boys. a. Which of the below are the three conditions for a binomial distribution? 1. The n trials are independent. III. The n trials are dependent. V. There are two trials. OA. III, V, and VI OB. II, III, and V C. I, IV, and VI OD. I, II, and IV b. n = 4 p= I II. Each trial has at least two possible outcomes. IV. Each trial has the same probability of a success. VI. Each trial has two possible outcomes.

MATLAB: An Introduction with Applications
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9.

**Educational Text: Understanding Binomial Distribution**

**Introduction:**
This exercise explores the concept of binomial distribution—a fundamental aspect of probability theory. We begin by considering the probabilities regarding the gender of newborns. Assume that each newborn baby has a probability of approximately 0.52 (52%) of being female and 0.48 (48%) of being male.

**Problem Statement:**
For a family with four children, let \( X \) represent the number of children who are girls. The following tasks are presented:

a. Identify the three conditions that must be satisfied for \( X \) to follow a binomial distribution.

b. Identify \( n \) and \( p \) for the binomial distribution.

c. Find the probability that the family has two girls and two boys.

**a. Conditions for a Binomial Distribution:**
The multiple-choice question asks which of the following conditions are necessary for a binomial distribution:

I. The \( n \) trials are independent.

II. Each trial has at least two possible outcomes.

III. The \( n \) trials are dependent.

IV. Each trial has the same probability of a success.

V. There are two trials.

VI. Each trial has two possible outcomes.

The correct answer is C: I, IV, and VI.

- I: The \( n \) trials should be independent.
- IV: Each trial should have the same probability of success.
- VI: Each trial should have precisely two possible outcomes (success/failure).

**b. Parameters for the Binomial Distribution:**
- \( n = 4 \): The number of trials (children).
- \( p = \): The probability of success (having a girl), which is 0.52.

**c. Probability of Two Girls and Two Boys:**
This section involves calculating the probability of obtaining exactly two girls and two boys. The solution would use the binomial probability formula:

\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]

where \( \binom{n}{k} \) is the binomial coefficient.

**Conclusion:**
Understanding these conditions and calculations allows us to model real-world scenarios using binomial distribution effectively. By applying the conditions and formulas, predictions regarding probabilistic events can be made with more accuracy.
Transcribed Image Text:**Educational Text: Understanding Binomial Distribution** **Introduction:** This exercise explores the concept of binomial distribution—a fundamental aspect of probability theory. We begin by considering the probabilities regarding the gender of newborns. Assume that each newborn baby has a probability of approximately 0.52 (52%) of being female and 0.48 (48%) of being male. **Problem Statement:** For a family with four children, let \( X \) represent the number of children who are girls. The following tasks are presented: a. Identify the three conditions that must be satisfied for \( X \) to follow a binomial distribution. b. Identify \( n \) and \( p \) for the binomial distribution. c. Find the probability that the family has two girls and two boys. **a. Conditions for a Binomial Distribution:** The multiple-choice question asks which of the following conditions are necessary for a binomial distribution: I. The \( n \) trials are independent. II. Each trial has at least two possible outcomes. III. The \( n \) trials are dependent. IV. Each trial has the same probability of a success. V. There are two trials. VI. Each trial has two possible outcomes. The correct answer is C: I, IV, and VI. - I: The \( n \) trials should be independent. - IV: Each trial should have the same probability of success. - VI: Each trial should have precisely two possible outcomes (success/failure). **b. Parameters for the Binomial Distribution:** - \( n = 4 \): The number of trials (children). - \( p = \): The probability of success (having a girl), which is 0.52. **c. Probability of Two Girls and Two Boys:** This section involves calculating the probability of obtaining exactly two girls and two boys. The solution would use the binomial probability formula: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] where \( \binom{n}{k} \) is the binomial coefficient. **Conclusion:** Understanding these conditions and calculations allows us to model real-world scenarios using binomial distribution effectively. By applying the conditions and formulas, predictions regarding probabilistic events can be made with more accuracy.
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