??? Assume a population of 43, 49, 52, and 59. Assume that samples of size n = 2 are randomly selected with replacement from the population. Listed below are the sixteen different samples. Complete parts (a) through (c).43, 43 43, 49 43, 52 43, 59 49, 43 49, 49 49, 52 49, 59 52, 43 52, 49 52, 52 52, 59 59, 43 59, 49 59, 52 59, 59 a. Find the median of each of the sixteen samples, then summarize the sampling distribution of the medians in the format of a table representing the probability distribution of the distinct median values. Use ascending order of the sample medians.\[ \begin{array}{|c|c|c|c|}\hline\text{Sample Median} & \text{Probability} & \text{Sample Median} & \text{Probability} \\\hline\quad & \quad & \quad & \quad \\\hline\quad & \quad & \quad & \quad \\\hline\quad & \quad & \quad & \quad \\\hline\quad & \quad & \quad & \quad \\\hline\end{array} \](Type integers or simplified fractions. Use ascending order of the sample medians.)

Name: ??? Assume a population of 43, 49, 52, and 59. Assume that samples of
Uploaded: 2024-03-20T07:07:37.000Z
Channel: Bartleby
Description: ??? Assume a population of 43, 49, 52, and 59. Assume that samples of size n = 2 are randomly selected with replacement from the population. Listed below are the sixteen different samples. Complete parts (a) through (c).43, 43 43, 49 43, 52 43, 59

The median for n=2 (even) is given as : median = n2th ordered value + (n2+1)th ordered value2= 1st ordered value +2nd ordered value2 The medians of the sixteen samples are given as : values median 43,43 43 43,49 46 43,52 47.5 43,59 51 49,43 46 49,49 49 49,52 50.5 49,59 54 52,43 47.5 52,49 50.5 52,52 52 52,59 55.5 59,43 51 59,49 54 59,52 55.5 59,59 59 The sampling distribution of the median is obtained as : Median probability 43 1/16 46 2/16 47.5 2/16 49 1/16 50.5 2/16 51 2/16 52 1/16 54 2/16 55.5 2/16 59 1/16 Total 1