Assıme an equal mean number of visitors per day as a null hypothesis To test for the goodness of fit of the above, the (Chi- square) value is:
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- An ecologist is studying the impact of local polluted waters on the growth of alligators. The length of adult male alligators typically follows a normal distribution with a standard deviation of 2 feet. The ecologist wants to estimate the mean length of this population of alligators. Suppose she samples n alligators at random and uses the sample mean, X to as an estimator for u. a. What is the bias and variance of the estimator? (Note, these may be a function of n.) b. If n = 4, what is the probability that the estimator is within one foot of the true mean? (I.e. find P(|X – µ| < 1). c. What sample size, n, is required for the estimator to be within one foot of the true mean with 95% probability? (I.e. find the value of n that satisfies P(|X – µ| < 1) = 0.95.) d. Suppose the ecologist ends up sampling n = 9 alligators and calculates a sample mean of ī = 10.4 feet. Construct a 95% confidence interval for the population mean. e. Give an interpretation for the interval obtained in (d).Many people believe that the average number of Facebook friends is 150. The population standard deviation is 37.6. A random sample of 46 high school students in a particular county revealed that the average number of Facebook friends was 159. At =α0.01, is there sufficient evidence to conclude that the mean number of friends is greater than 150? A. State the hypotheses and identify the claim with the correct hypothesis. :H0 ▼claim or not claim :H1 ▼claim or not claimThis hypotheses test is a ▼one-tailed or two-tailed test B. Find the critical value(s) (c)Compute the test value. z= (d)Make the decision. reject or accept (e)Summarize the results. is there enough evidence to support the claimIn a left-tailed hypothesis for a population mean where the population standard deviation is unknown, the test statistic for a random sample size 18 was calculated to be -4.0545. Determine the P-value for the test. X
- 10The one-sample t-test accounts for bias resulting from sample size in the calculation of the standard error of the mean by: Group of answer choices dividing by the square root of the sample size minus one. incorporating the difference between the sample mean and population mean incorporating the sample standard deviation dividing by the population standard deviationThe null hypothesis for a repeated-measures test states O cach individual will have a difference score of D-0 the overall sample will have a mean difference of Mo -0 O the entire population will have a mean difference of do -0 O Allof the other options are correct
- When interpreting a standard deviation how do I know whether its an empirical rule or Chebychev? The number of standard deviations? and how would I compute that?A researcher is 98% confident with the estimate of a sample, of standard deviation 5, that the error will not be more than 2. What are the given? What is the sample size needed by the researcher?In the past, the mean running time for a certain type of flashlight battery has been 9.6 hours. The manufacturer has introduced a change in the production method and wants to perform a hypothesis test to determine whether the mean running time has decreased as a result. A hypothesis test is to be performed. Determine the null and alternative hypotheses. A. H0: µ ¥ 9.6 hours and H1: µ = 9.6 hours B. H0: µ = 9.6 hours and H1: µ ¥ 9.6 hours C. H0: µ = 9.6 hours and H1: µ > 9.6 hours D. H0: µ = 9.6 hours and H1: µ < 9.6 hours
- A survey about allergic reactions revealed that 84 out of randomly selected 158 people exhibit allergic symptoms. The percentage of the whole country is believed to be 25% for such allergic symptoms. Find the test statistic for hypothesis testing at right tail. (Sensitivity 0.00)Milan n.nA market researcher wants to determine whether a new model of a personal computer that had been advertised on a late-night talk show had achieved more brand-name recognition among people who watched the show regularly than among people who did not. After conducting a survey, it was found that 12% of all people both watched the show regularly and could correctly identify the product. Also, 13% of all people regularly watched the show and 39% of all people could correctly identify the product. Define a pair of random variables as shown below. Complete parts (a) through (c). X=1 if regularly watch the show Y=1 if product correctly identified a. Find the joint probability function of X and Y X 0 1 (Do not round.) 0 X=0 otherwise Y=0 otherwise 1 CLLL 2 xdex ram