Assignmen Let p, 0)=2+f,P2(1)=t-4, P3(1) = 4 +t-21 Complete parts and (b) below. a. Use coordinate vectors to show that these polynomials form a basis for P. What are the coordinate vectors corresponding to p,, P2, and p3? 2 P = P2 = Pa = - 2 Place these coordinate vectors into the columns of a matrix A. What can be said about the matrix A? OA The matrix A is invertible because it is row equivalent to la and therefore the row reduced columns of A form a basis for R3 by the Invertible Matrix Theorem. OB. The matrix A is invertible because it is row equivalent tol, and therefore the null space of A, denoted Nul A, forms a basis for R3 by the Invertible Matrix Theorem. OC The matrix A forms a basis for R3 by the Invertible Matriix Theorem because all square matrices are row equivalent to . 0. The matrbx A is invertible because it is row equivalent to l, and therefore the original columns of A form a basis for R3 by the Invertible Matrix Theorem. How does this show that the polynomials form a basis for P2? OA The polynomials form a basis for P, because any basis in Rn is also a basis in P, DB The polynomials form a basis for P, because the columns of A are linearly independent OC The polynomials form a basis for P, because the matrix A is invertible D. The polynomials form a basis for P, because of the isomorphism between R and P. b Consider the basis B= (p,. P2 P3) for P2 Find q in Pa given that [q]e = q)= ( t-C

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Assignmen
Let p, (1)=2+f, P2(1)=t- 4t², P3(1) = 4 +t- 21². Complete parts (a) and (b) below.
a. Use coordinate vectors to show that these polynomials form a basis for P.
What are the coordinate vectors corresponding to p, , p2, and p3?
4.
P =
P2 =
.P3 =
Place these coordinate vectors into the columns of a matrix A. What can be said about the matrix A?
OA The matrix A is invertible because it is row equivalent to la and therefore the row reduced columns of A form a basis for R³ by the Invertible Matrix Theorem.
O B. The matrix A is invertible because it is row equivalent to |, and therefore the null space of A, denoted Nul A, forms a basis for R3 by the Invertible Matrix Theorem.
OC. The matrix A forms a basis for R3 by the Invertible Matrix Theorem because all square matrices are row equivalent to l,
0. The matrix A is invertible because it is row equivalent to l, and therefore the original columns of A form a basis for R³ by the Invertible Matrix Theorem.
How does this show that the polynomials form a basis for P,?
OA. The polynomials form a basis for P, because any basis in Rr is also a basis in P.
OB The polynomials form a basis for P, because the columns of A are linearly independent.
OC The polynomials form a basis for P, because the matrix A is invertible.
The polynomials form a basis for P, because of the isomorphism between R3 and P.
b. Consider the basis B= (p,. P2. Pa) for P, Find q in P given that [q]e =|
qt) =
Transcribed Image Text:Assignmen Let p, (1)=2+f, P2(1)=t- 4t², P3(1) = 4 +t- 21². Complete parts (a) and (b) below. a. Use coordinate vectors to show that these polynomials form a basis for P. What are the coordinate vectors corresponding to p, , p2, and p3? 4. P = P2 = .P3 = Place these coordinate vectors into the columns of a matrix A. What can be said about the matrix A? OA The matrix A is invertible because it is row equivalent to la and therefore the row reduced columns of A form a basis for R³ by the Invertible Matrix Theorem. O B. The matrix A is invertible because it is row equivalent to |, and therefore the null space of A, denoted Nul A, forms a basis for R3 by the Invertible Matrix Theorem. OC. The matrix A forms a basis for R3 by the Invertible Matrix Theorem because all square matrices are row equivalent to l, 0. The matrix A is invertible because it is row equivalent to l, and therefore the original columns of A form a basis for R³ by the Invertible Matrix Theorem. How does this show that the polynomials form a basis for P,? OA. The polynomials form a basis for P, because any basis in Rr is also a basis in P. OB The polynomials form a basis for P, because the columns of A are linearly independent. OC The polynomials form a basis for P, because the matrix A is invertible. The polynomials form a basis for P, because of the isomorphism between R3 and P. b. Consider the basis B= (p,. P2. Pa) for P, Find q in P given that [q]e =| qt) =
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