Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is (2, 1, 2, 2) and matchValue is 2, then numMatches should be 3. Your code will be tested with the following values: matchValue: 2, userValues: (2, 1, 2, 2) (as in the example program above) matchValue: 0, userValues: (0, 0, 0, 0) matchValue: 10, userValues: (20, 50, 70, 100) (Notes) 422784.2543518.qx3zay7 6 7 8 96 10 11 12 13 14 15 16 17 18 19 20 21 22} } final int NUM_VALS = 4; int[] userValues new int [NUM_VALS]; int i; int matchValue; int numMatches = -99; // Assign numMatches with before your for Loop matchValue scnr.nextInt(); for (i = 0; i < userValues.length; ++i) { userValues[i] = scnr.nextInt (); } /* Your solution goes here */ System.out.println("matchValue: + matchValue + ", numMatches: + numMatches);
Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is (2, 1, 2, 2) and matchValue is 2, then numMatches should be 3. Your code will be tested with the following values: matchValue: 2, userValues: (2, 1, 2, 2) (as in the example program above) matchValue: 0, userValues: (0, 0, 0, 0) matchValue: 10, userValues: (20, 50, 70, 100) (Notes) 422784.2543518.qx3zay7 6 7 8 96 10 11 12 13 14 15 16 17 18 19 20 21 22} } final int NUM_VALS = 4; int[] userValues new int [NUM_VALS]; int i; int matchValue; int numMatches = -99; // Assign numMatches with before your for Loop matchValue scnr.nextInt(); for (i = 0; i < userValues.length; ++i) { userValues[i] = scnr.nextInt (); } /* Your solution goes here */ System.out.println("matchValue: + matchValue + ", numMatches: + numMatches);
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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![CTU - Class X zy Section 3.6 × zy Section 3.1 x zy Section 2.9 x zy Section 3.3 x zy Section 2.1 x
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learn.zybooks.com/zybook/CS226-2204A-03-2204A/chapter/3/section/6
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= zyBooks My library > CS 226T: Java Programming home > 3.6: Iterating through arrays
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3.6.2: Finding values in an array.
+
Type here to search
Your code will be tested with the following values:
matchValue: 2, userValues: (2, 1, 2, 2} (as in the example program above)
matchValue: 0, userValues: (0, 0, 0, 0)
matchValue: 10, userValues: (20, 50, 70, 100)
(Notes)
422784.2543518.qx3zqy7
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Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex:
If userValues is {2, 1, 2, 2) and matchValue is 2, then numMatches should be 3.
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22}
Run
}
final int NUM_VALS = 4;
int[] userValues = new int [NUM_VALS];
matchValue = scnr.nextInt ();
for (i = 0; i < userValues.length; ++i) {
userValues[i] = scnr.nextInt ();
}
/* Your solution goes here */
int i;
int matchValue;
int numMatches = -99; // Assign numMatches with before your for Loop
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System.out.println("matchValue: " + matchValue + ", numMatches: " + numMatches);
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Transcribed Image Text:CTU - Class X zy Section 3.6 × zy Section 3.1 x zy Section 2.9 x zy Section 3.3 x zy Section 2.1 x
← → CO
learn.zybooks.com/zybook/CS226-2204A-03-2204A/chapter/3/section/6
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= zyBooks My library > CS 226T: Java Programming home > 3.6: Iterating through arrays
CHALLENGE
ACTIVITY
3.6.2: Finding values in an array.
+
Type here to search
Your code will be tested with the following values:
matchValue: 2, userValues: (2, 1, 2, 2} (as in the example program above)
matchValue: 0, userValues: (0, 0, 0, 0)
matchValue: 10, userValues: (20, 50, 70, 100)
(Notes)
422784.2543518.qx3zqy7
6
7
8
9
10
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12
13
14
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Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex:
If userValues is {2, 1, 2, 2) and matchValue is 2, then numMatches should be 3.
20
21
22}
Run
}
final int NUM_VALS = 4;
int[] userValues = new int [NUM_VALS];
matchValue = scnr.nextInt ();
for (i = 0; i < userValues.length; ++i) {
userValues[i] = scnr.nextInt ();
}
/* Your solution goes here */
int i;
int matchValue;
int numMatches = -99; // Assign numMatches with before your for Loop
Extended Protectio....
O
CTU Messe X zy Catalog
발
System.out.println("matchValue: " + matchValue + ", numMatches: " + numMatches);
m
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× b Answered: x +
Q
GlobalConnect
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zyBooks catalog Help/FAQ Stacey Queen
1 tast
passed
All tests
0 X
57°F Mostly cloudy
☆ ☐K Paused
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8/28/2022
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![CTU - Class X zy Section 3.6 × zy Section 3.1 x zy Section 2.9 x zy Section 3.3 x zy Section 2.1 x
← → CO
learn.zybooks.com/zybook/CS226-2204A-03-2204A/chapter/3/section/6
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= zyBooks My library > CS 226T: Java Programming home > 3.6: Iterating through arrays
CHALLENGE
ACTIVITY
3.6.2: Finding values in an array.
+
Type here to search
Your code will be tested with the following values:
matchValue: 2, userValues: (2, 1, 2, 2} (as in the example program above)
matchValue: 0, userValues: (0, 0, 0, 0)
matchValue: 10, userValues: (20, 50, 70, 100}
(Notes)
422784.2543518.qx3zqy7
1 import java.util.Scanner;
2
3 public class FindMatchValue {
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Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex:
If userValues is {2, 1, 2, 2) and matchValue is 2, then numMatches should be 3.
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II
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Run
public static void main (String[] args) {
Scanner scnr = new Scanner(System.in);
final int NUM_VALS = 4;
int[] userValues = new int [NUM_VALS];
int i;
matchValue = scnr.nextInt ();
for (i = 0; i < userValues.length; ++i) {
userValues[i] = scnr.nextInt ();
}
O
Extended Protectio....
int matchValue;
int numMatches = -99; // Assign numMatches with before your for Loop
발
CTU Messe X zy Catalog
m
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passed
All tests
0 X
57°F Mostly cloudy
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LIBERTY SHIELD
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8/28/2022
⠀](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F788fc729-a951-45c4-9909-47eea7bbf82f%2Fb1eee20d-27f2-493d-a2f6-83a96a9fa050%2Fiiwu0jn_processed.png&w=3840&q=75)
Transcribed Image Text:CTU - Class X zy Section 3.6 × zy Section 3.1 x zy Section 2.9 x zy Section 3.3 x zy Section 2.1 x
← → CO
learn.zybooks.com/zybook/CS226-2204A-03-2204A/chapter/3/section/6
Vision Menu - Login ec2019 F& Protective / F&I caf...
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= zyBooks My library > CS 226T: Java Programming home > 3.6: Iterating through arrays
CHALLENGE
ACTIVITY
3.6.2: Finding values in an array.
+
Type here to search
Your code will be tested with the following values:
matchValue: 2, userValues: (2, 1, 2, 2} (as in the example program above)
matchValue: 0, userValues: (0, 0, 0, 0)
matchValue: 10, userValues: (20, 50, 70, 100}
(Notes)
422784.2543518.qx3zqy7
1 import java.util.Scanner;
2
3 public class FindMatchValue {
4
5
6
7
8
Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex:
If userValues is {2, 1, 2, 2) and matchValue is 2, then numMatches should be 3.
9
10
11
II
12
13
14
15
16
17
Run
public static void main (String[] args) {
Scanner scnr = new Scanner(System.in);
final int NUM_VALS = 4;
int[] userValues = new int [NUM_VALS];
int i;
matchValue = scnr.nextInt ();
for (i = 0; i < userValues.length; ++i) {
userValues[i] = scnr.nextInt ();
}
O
Extended Protectio....
int matchValue;
int numMatches = -99; // Assign numMatches with before your for Loop
발
CTU Messe X zy Catalog
m
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× b Answered: x +
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passed
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