Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is {2, 1, 2, 2} and matchValue is 2, then numMatches should be 3. Your code will be tested with the following values: matchValue: 2, userValues: {2, 1, 2, 2} (as in the example program above) matchValue: 0, userValues: {0, 0, 0, 0} matchValue: 10, userValues: {20, 50, 70, 100} (Notes)
Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is {2, 1, 2, 2} and matchValue is 2, then numMatches should be 3. Your code will be tested with the following values: matchValue: 2, userValues: {2, 1, 2, 2} (as in the example program above) matchValue: 0, userValues: {0, 0, 0, 0} matchValue: 10, userValues: {20, 50, 70, 100} (Notes)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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![Assign `numMatches` with the number of elements in `userValues` that equal `matchValue`. `userValues` has `NUM_VALS` elements. For example, if `userValues` is {2, 1, 2, 2} and `matchValue` is 2, then `numMatches` should be 3.
Your code will be tested with the following values:
- `matchValue`: 2, `userValues`: {2, 1, 2, 2} (as in the example program above)
- `matchValue`: 0, `userValues`: {0, 0, 0, 0}
- `matchValue`: 10, `userValues`: {20, 50, 70, 100}
(Notes)
```c
#include <stdio.h>
int main(void) {
const int NUM_VALS = 4;
int userValues[NUM_VALS];
int i;
int matchValue;
int numMatches = -99; // Assign numMatches with 0 before your for loop
scanf("%d", &matchValue);
for (i = 0; i < NUM_VALS; ++i) {
scanf("%d", &(userValues[i]));
}
/* Your solution goes here */
printf("matchValue: %d, numMatches: %d\n", matchValue, numMatches);
return 0;
}
```
- The section to add the solution is marked by a comment.
- This program is designed to read a value for `matchValue` and an array `userValues` of size `NUM_VALS`. It then calculates how many times `matchValue` appears in the `userValues` array and stores the count in `numMatches`.
- The example includes two tested scenarios with specific values for `matchValue` and `userValues`.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F877d147a-40f9-47d8-b25c-41d77d376d71%2Fdf245deb-e0ad-4fcc-8185-1bdfdc760009%2Fzktp3jr_processed.png&w=3840&q=75)
Transcribed Image Text:Assign `numMatches` with the number of elements in `userValues` that equal `matchValue`. `userValues` has `NUM_VALS` elements. For example, if `userValues` is {2, 1, 2, 2} and `matchValue` is 2, then `numMatches` should be 3.
Your code will be tested with the following values:
- `matchValue`: 2, `userValues`: {2, 1, 2, 2} (as in the example program above)
- `matchValue`: 0, `userValues`: {0, 0, 0, 0}
- `matchValue`: 10, `userValues`: {20, 50, 70, 100}
(Notes)
```c
#include <stdio.h>
int main(void) {
const int NUM_VALS = 4;
int userValues[NUM_VALS];
int i;
int matchValue;
int numMatches = -99; // Assign numMatches with 0 before your for loop
scanf("%d", &matchValue);
for (i = 0; i < NUM_VALS; ++i) {
scanf("%d", &(userValues[i]));
}
/* Your solution goes here */
printf("matchValue: %d, numMatches: %d\n", matchValue, numMatches);
return 0;
}
```
- The section to add the solution is marked by a comment.
- This program is designed to read a value for `matchValue` and an array `userValues` of size `NUM_VALS`. It then calculates how many times `matchValue` appears in the `userValues` array and stores the count in `numMatches`.
- The example includes two tested scenarios with specific values for `matchValue` and `userValues`.
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