Aspirin (acetylsalicylic acid, HC9H,0.) has a value of Ka equal to 3.3 x 10-4. What is the pH after 652 mng of aspirin is dissolved in a solution of 237 mL? PREV 1 NEXT Based on your ICE table and definition of Ka, set up the expression for Ka in order to determine the unknown. Do not combine or simplify terms. Ka 3.3 x 10-4 %3D

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Question 15 of 27
Aspirin (acetylsalicylic acid, HC,H,O,) has a value of Ka equal to 3.3 x 10-4.
What is the pH after 652 mg of aspirin is dissolved in a solution of 237 mL?
1
NEXT
Based on the given values, set up ICE table in order to determine the unknown.
HC,H,0,(aq) +
H20(I)
H3O*(aq)
C9H,O4 (aq)
Initial (M)
Change (M)
Equilibrium (M)
5 RESET
2.75 x 103
3.62 x 103
1.53 x 10-5
15.3
0.0153
+x
2.75 x 103 + x
2.75 x 103 - x
3.62 x 103 + x
3.62 x 103 - x
1.53 x 105 +
1.53 × 10-.
15.3 + x
-X
15.3 - x
0.0153 + x
0.0153 - x
Transcribed Image Text:Question 15 of 27 Aspirin (acetylsalicylic acid, HC,H,O,) has a value of Ka equal to 3.3 x 10-4. What is the pH after 652 mg of aspirin is dissolved in a solution of 237 mL? 1 NEXT Based on the given values, set up ICE table in order to determine the unknown. HC,H,0,(aq) + H20(I) H3O*(aq) C9H,O4 (aq) Initial (M) Change (M) Equilibrium (M) 5 RESET 2.75 x 103 3.62 x 103 1.53 x 10-5 15.3 0.0153 +x 2.75 x 103 + x 2.75 x 103 - x 3.62 x 103 + x 3.62 x 103 - x 1.53 x 105 + 1.53 × 10-. 15.3 + x -X 15.3 - x 0.0153 + x 0.0153 - x
Should
Question 15 of 27
Aspirin (acetylsalicylic acid, HC9H,0.) has a value of Ka equal to 3.3 x 10-4.
What is the pH after 652 mg of aspirin is dissolved in a solution of 237 mL?
PREV
1
2
3
NEXT
Based on your ICE table and definition of Ka, set up the expression for Ka in order to determine
the unknown. Do not combine or simplify terms.
Ka
= 3.3 x 104
%3!
5 RESET
[0]
[2.75 × 10³]
[3.62 x 10]
[1.53 × 10-]
[15.3]
[0.0153]
[x]
[2x]
[2.75 x 103 + x]
[2.75 x 103 - x]
[3.62 x 103 + x]
[3.62 x 103 - x]
[1.53 x 10-5 + x]
[1.53 x 10-5 - x]
[15.3 + x]
[15.3 - x]
[0.0153 + x]
[0.0153 - x]
Transcribed Image Text:Should Question 15 of 27 Aspirin (acetylsalicylic acid, HC9H,0.) has a value of Ka equal to 3.3 x 10-4. What is the pH after 652 mg of aspirin is dissolved in a solution of 237 mL? PREV 1 2 3 NEXT Based on your ICE table and definition of Ka, set up the expression for Ka in order to determine the unknown. Do not combine or simplify terms. Ka = 3.3 x 104 %3! 5 RESET [0] [2.75 × 10³] [3.62 x 10] [1.53 × 10-] [15.3] [0.0153] [x] [2x] [2.75 x 103 + x] [2.75 x 103 - x] [3.62 x 103 + x] [3.62 x 103 - x] [1.53 x 10-5 + x] [1.53 x 10-5 - x] [15.3 + x] [15.3 - x] [0.0153 + x] [0.0153 - x]
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