Based on their records, a hospital claims that the proportion, p, of full-term babies born in the community that weigh more than 7 pounds is 39%. Apediatrician who works with several hospitals in the community would like to verify the hospital's claim. In a random sample of 155 babies born in thecommunity, 55 weighed over 7 pounds. Is there enough evidence to reject the hospital's claim at the 0.05 level of significance?Perform a two-tailed test. Then complete the parts below.Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.)(a) State the null hypothesis Ho and the alternative hypothesis H₁.H :OH₁ :0(b) Determine the type of test statistic to use.(Choose one) ▼(c) Find the value of the test statistic. (Round to three or more decimal places.)(d) Find the p-value. (Round to three or more decimal places.)(e) Can we reject the claim that the proportion of full-term babies born in thecommunity that weigh more than 7 pounds is 39%?O Yes O No3.X0=0aXSOSOРP0200#0 0<0 ☐>03

Answered: Image /qna-images/answer/77ca26f6-dc04-4738-814d-ae62a9abc9eb.jpg

Answered: ased on their records, a hospital…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Calcium is the most abundant mineral in the body and also one of the most important. The recommended daily allowance (RDA) of calcium for adults is 800 milligrams (mg). A random sample of 18 people with incomes below the poverty level gives the following daily calcium intakes: 686, 433, 743, 647, 734, 641, 993, 620, 574, 634, 850, 858, 992, 775, 1113, 672, 879, 609 At the 1% significance level, do the data provides sufficient evidence to conclude that the mean calcium intake of all people with income levels below the poverty level is less than the RDA of 800 mg? Step 1 : Step 2: 3.Critical Value approach: 4.Conclusion:
A study is to be made to estimate the proportion of residents of a certain city and its suburbs who favor the construction of a nuclear power plant near the city. How large a sample is needed if one wishes to be at least 95% confident that the estimate is within 0.08 of the true proportion of residents who favor the construction of the nuclear power plant?
Past studies have indicated that the percentage of smokers was estimated to be about 30%. Given the new smoking cessation programs that have been implemented, you now believe that the percentage of smokers has reduced. You randomly surveyed 2414 people and found that 680 smoke. Use a 0.05 significance level to test the claim that the percentage of smokers has reduced. a) Identify the null and alternative hypotheses? Hp: ? v H:? v b) What type of hypothesis test should you conduct (left-, right-, or two-tailed)? O left-tailed O right-tailed O two-tailed c) Identify the appropriate significance level. Check Answer
A time analyst for the Super-Fast speedway pit crew observed the mechanic in charge of changing both front tires during a pit-stop practice session. The mechanic’s job is divided into six work elements and a preparation time between drills. The element times (in seconds) for the first six cycles are shown in Table.a. Calculate the normal time for changing tires.b. What sample size is appropriate for estimating the average time for work element 3 within +-1 percent of the true mean with 99 percent confidence?c. What is the standard time for changing tires if the allowance is 20 percent?
It is believed that 11% of all Americans are left-handed. A college needs to know how many left-handed desks to place in the big lecture halls being constructed on its campus. In a random sample of 120 students of its 12124 students, 15 were left-handed. Does this provide enough evidence to show that students at this college have a higher percentage of left-handers than the general American population? Use a 10% level of significance.
Vita Pills were advertised as having 751 mg of vitamin C per pill. A marketing firm hypothesizes that the amount of vitamin C is more than what is advertised. What can be concluded with α = 0.10. The vitamin C content per pill from a sample of pills is as follows:701, 761, 716, 721, 751, 721, 711, 741. A) What is the appropriate test statistic? B) Population and sample? C) Obtain/compute the appropriate values to make a decision about H0. Critical value= Tests statistic= D)Compute the corresponding effect size(s) and indicate magnitude(s). d= r2= E)Make an interpretation based on the results. The amount of vitamin C in Vita Pills is significantly more than the advertised claim. The amount of vitamin C in Vita Pills is significantly less than the advertised claim. The amount of vitamin C in Vita Pills is not significantly different than the advertised claim ---Select--- marketing firm advertisement Vita Pills sample of pills vitamin C ---Select--- marketing…
A company claims that at least 94% of equipment supplied to a manufacturer is within specifications. A test of a sample of 200 pieces of equipment showed that 27 of them were faulty. Test their claim at the 5% significance level?
When a poultry farmer uses his regular feed, the newborn chickens have normally distributed weights with a mean of 62.462.4 oz. In an experiment with an enriched feed mixture, ten chickens are born with the following weights (in ounces). 66.5, 64.4, 64.6, 65.5, 66.3, 67.4, 66, 62.4, 65.9, 6266.5, 64.4, 64.6, 65.5, 66.3, 67.4, 66, 62.4, 65.9, 62 Use the α=0.01α=0.01 significance level to test the claim that the mean weight is higher with the enriched feed. (a) The sample mean is x⎯⎯⎯=x¯= (b) The sample standard deviation is s=s= (c) The test statistic is t=t= (d) The critical value is t∗=t∗= (e) The conclusion is
Please help me in answering the following practice question:Given a random sample of the amount of protein (in gram) in one bag of snack food: 0.95, 0.85, 0.92, 0.95, 0.93, 0.86, 1, 0.92, 0.85, 0.81, 0.78, 0.93, 0.93, 1.05, 0.93, 1.06, 1.06, 0.96, 0.81, 0.96 Here, it is assumed that the amount of protein in the snack is normal. How would I calculate a 98% two-sided confidence interval for the average amount of protein in one bag?Thank you for your help in advance!
According to previous studies, 12% of the U.S. population is left-handed. Not knowing this, a high school student claims that the percentage of left-handed people in the U.S. is 14%. The student is going to take a random sample of 1650 people in the U.S. to try to gather evidence to support the claim. Let p be the proportion of left-handed people in the sample. Answer the following. (If necessary, consult a list of formulas.) ✔ (a) Find the mean of p. P. 0 (b) Find the standard deviation of p. (c) Compute an approximation for P (P<0.14), which is the probability that there will be 14% or fewer left-handed people in the sample. Round your answer to four decimal places. X
webassign.net/web/Student/Assignment-Responses/submit?pos=10&dep=22704121&tags=autos A newspaper infographic titled "Social Media Jeopardizing Your Job?" summarized data from a survey of 1,825 recruiters and human resource professionals. The infographic indicated that 53% of the people surveyed had reconsidered a job candidate based on his or her social media profile. Assume that the sample is representative of the population of recruiters and human resource professionals in the United States. (a) Use the given information to estimate the proportion of recruiters and human resource professionals who have reconsidered a job candidate based on his or her social media profile using a 95% confidence interval. (Use a table or technology. Round your answers to three decimal places.) Give an interpretation of the interval in context. There is a 95% chance that the true proportion of recruiters and human resource professionals who have reconsidered a job candidate based on his or her social…

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