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Aşağıdaki lineer sistemi LU Faktorizasyonu yöntemi ile çözerek çözümün ilk bileşenini (₁) ve U matrisinin ikinci satır, üçüncü sütun elemanını ( U23) bulunuz. Solve the following system by applying the LU-Factorization method and find the first component (1) of the solution and the second row, third column entry (U23) of the matrix U. 2x₁+3x₂-x3=5 4x₁+4x₂-3x3=3 2x₁+3x2+4x3=2 x1 = -1, U23 21 O x₁ O 1 X1 = 2, 423 - = - 1, U23 - = = 2, U23 = 0 : 0 3 1,423 = 3 -1

Aşağıdaki lineer sistemi LU Faktorizasyonu yöntemi ile çözerek çözümün ilk bileşenini (₁) ve U matrisinin ikinci satır, üçüncü sütun elemanını ( U23) bulunuz. Solve the following system by applying the LU-Factorization method and find the first component (1) of the solution and the second row, third column entry (U23) of the matrix U. 2x₁+3x₂-x3=5 4x₁+4x₂-3x3=3 2x₁+3x2+4x3=2 x1 = -1, U23 21 O x₁ O 1 X1 = 2, 423 - = - 1, U23 - = = 2, U23 = 0 : 0 3 1,423 = 3 -1

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Aşağıdaki lineer sistemi LU Faktorizasyonu yöntemi ile çözerek çözümün ilk bileşenini (₁) ve U matrisinin ikinci satır, üçüncü sütun elemanını ( U23) bulunuz. Solve the following system by applying the LU-Factorization method and find the first component (1) of the solution and the second row, third column entry (U23) of the matrix U. 2x₁+3x₂-x3=5 4x₁+4x₂-3x3=3 2x₁+3x₂+4x3=2 x1 = -1, U23 21 O x₁ O x1 x1 = 2, 423 - = - 1, U23 = = 2, U23 = 0 - = 3 : 0 1, U23 27 = 3 -1
Transcribed Image Text:Aşağıdaki lineer sistemi LU Faktorizasyonu yöntemi ile çözerek çözümün ilk bileşenini (₁) ve U matrisinin ikinci satır, üçüncü sütun elemanını ( U23) bulunuz. Solve the following system by applying the LU-Factorization method and find the first component (1) of the solution and the second row, third column entry (U23) of the matrix U. 2x₁+3x₂-x3=5 4x₁+4x₂-3x3=3 2x₁+3x₂+4x3=2 x1 = -1, U23 21 O x₁ O x1 x1 = 2, 423 - = - 1, U23 = = 2, U23 = 0 - = 3 : 0 1, U23 27 = 3 -1
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