As shown below, a charged particle is moving through a region that has a uniform E-field (the red lines) and a uniform 17.3 T B-field. As a result of these two fields and the resulting forces (ignore gravity), the particle has a constant velocity of 328 m/s.A.) Determine the directions of F= & FB on the particle.Direction of F=Choose direction +Direction of FBChoose directionB.) Determine the magnitude of the E-field and the direction of the B-field. Assume that the B-field is perpendicular to the velocity.E =Direction of B:Choose direction

Given a charged particle moving in a uniform electric field and a uniform magnetic field B=17.3T…

Answered: As shown below, a charged particle is…

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