As shown below, a charged particle is moving through a region that has a uniform E-field (the red lines) and a uniform 17.3 TB-field. As a result of these two fields and the resulting forces (ignore gravity), the particle has a constant velocity of 328 mis. A.) Determine the directions of Fe & Fg on the particle. Direction of FE -Choose direction : Direction of Fs =Choose direction : B.) Determine the magnitude of the E-field and the direction of the B-field. Assume that the B-field E- perpendicular to the velocity. Direction of B = Choose direction :
As shown below, a charged particle is moving through a region that has a uniform E-field (the red lines) and a uniform 17.3 TB-field. As a result of these two fields and the resulting forces (ignore gravity), the particle has a constant velocity of 328 mis. A.) Determine the directions of Fe & Fg on the particle. Direction of FE -Choose direction : Direction of Fs =Choose direction : B.) Determine the magnitude of the E-field and the direction of the B-field. Assume that the B-field E- perpendicular to the velocity. Direction of B = Choose direction :
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Transcribed Image Text:As shown below, a charged particle is moving through a region that has a uniform E-field (the red lines) and a uniform 17.3 T B-field. As a result of these two fields and the resulting forces (ignore gravity), the particle has a constant velocity of 328 m/s.
A.) Determine the directions of F= & FB on the particle.
Direction of F=
Choose direction +
Direction of FB
Choose direction
B.) Determine the magnitude of the E-field and the direction of the B-field. Assume that the B-field is perpendicular to the velocity.
E =
Direction of B:
Choose direction
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