As shown, a truss is loaded by the forces P = 492 lb and P3 = 197 1lb and has the dimension a = 10.3 ft . P, H - P2 E в с D a/2 al2

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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As shown, a truss is loaded by the forces P = 492 lb and P, = 197 lb and has the dimension a = 10.3 ft
Learning Goal:
To apply the method of sections to find the forces in
specific members of a truss.
i.
y
The method of sections is used to find the force in a
P1
specific member of a truss and is based on the
principle that, if a body is in equilibrium, then every
part of that body is also in equilibrium. When applied,
the method of sections "cuts" or sections the
members of a truss and exposes their internal forces.
To find the unknown internal member forces, the free-
body diagram of a section is drawn and the equations
of equilibrium are applied:
P2
a
E
EF. = 0
B
D
Σ-0
a/2
a/2
E Mo =0
Because there are only three independent equilibrium
equations, section cuts should be made such that
Determine FBC , the magnitude of the force in member BC, using the method of sections. Assume for your calculations that
each member is in tension, and include in your response the sign of each force that you obtain by applying this assumption.
there are not more than three members that have
Express your answer numerically in pounds to three significant figures.
unknown forces.
• View Available Hint(s)
vec
?
FBC =
lbs
Submit
P Pearson
Transcribed Image Text:I Review As shown, a truss is loaded by the forces P = 492 lb and P, = 197 lb and has the dimension a = 10.3 ft Learning Goal: To apply the method of sections to find the forces in specific members of a truss. i. y The method of sections is used to find the force in a P1 specific member of a truss and is based on the principle that, if a body is in equilibrium, then every part of that body is also in equilibrium. When applied, the method of sections "cuts" or sections the members of a truss and exposes their internal forces. To find the unknown internal member forces, the free- body diagram of a section is drawn and the equations of equilibrium are applied: P2 a E EF. = 0 B D Σ-0 a/2 a/2 E Mo =0 Because there are only three independent equilibrium equations, section cuts should be made such that Determine FBC , the magnitude of the force in member BC, using the method of sections. Assume for your calculations that each member is in tension, and include in your response the sign of each force that you obtain by applying this assumption. there are not more than three members that have Express your answer numerically in pounds to three significant figures. unknown forces. • View Available Hint(s) vec ? FBC = lbs Submit P Pearson
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