as each experiment will be ass that is roughly 10%-20% There is no need to be terr
as each experiment will be ass that is roughly 10%-20% There is no need to be terr
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I need help with question #12 from the submitted instruction image. Image number 2 is my work up to this point for information need to use. Can you show me how to do #12?

Transcribed Image Text:9. Now you will have to use some sound judgement, as each experiment will be slightly
different for each student. You should place some mass that is roughly 10%-20% of the mass
of the stick, on the zero end of your ruler/meter stick. There is no need to be terribly precise in
how much mass you add, just try to estimate the added mass given your answer in #5. You
should attach the mass so that the masses do not fall off, by using some tape. These masses
could be a few paperclips for a small ruler, or a few pens or pencils for a larger meter stick.
Now balance the stick on your finger ao you die in .,
: - ...
difference, the position of the finger! Take a photo or make a skeich of tine baianced stick and
notate the position of your finger in the space below.
10. From your photo or sketch, draw a force diagram including distances to the forces from
your finger.
11. Estimate how far the center of mass of the ruler or meter stick is from your finger. Write
out this distance below.
12. Using Newton's Second Law of Rotational Motion, write out the equation for the diagiam in
#10. Note that you can place actual numbers in for the weight of the ruler or meter stick and the
distance from the pivoting finger. Lastly, you know that the position of the added mass is on the
Cnd of tho suck. Csing the3S values, solve for the mass you added on the end of the stick.
Note: You may find it useful to this of the mass of ruler on a "per centimeter" basis. For
example, suppose you are balancing a 30 cm ruler that has a mass of 20 grams. This, then,
means that each centimeter of the ruiei has a máóó úf úbuut C.CT yıu... C ..
without any paper clips you may find that the equilibrium position of your finger is at 15 cm. This
would mean there is 15cm x 0.67 g/cm = 10 grams to left (and therefore to the right as well) of
the balance point.
13. Using your kitchen scale, a grocery scale, or google, estimate the mass of the objects you
used and compare this to the calculated mass in #12.

Transcribed Image Text:9 20'%. of 0.05 kg 0.01 kg
%3D
added
werght
finger position needs to move closer
to added weight(or side ot larger wight)
to balance (static eguilibrum)
Finger
F3
Fi メi
O F3 = F,+ F2 Center & Mass; aa,86 Conter of mass is 1alemfrom fencer
finger: a4,13 em (9.5")
『uier Gら sこの,0
d= lever center
1.27cm
90 513
4,130m
38.1cm ruler
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