Two blocks with masses m1= 3.00 kg and m2=4.00 kg are connected by a light piece of red string. The red string is draped over a frictionless pulley. Block m, is positioned on a rough ramp that makes an angle of 37.0° with the horizontal, while block m2 is positioned on a rough horizontal tabletop to the left of the ramp. The coefficient of kinetic friction between mị and the ramp is µi= 0.250, and the coefficient of kinetic friction between m2 and the ramp is µ2= 0.100. Meanwhile, a third block of mass m3 = 0.0250 kg is connected to the other side of mass m2 with a piece of blue string. The blue string is draped over a second frictionless pulley so that mass m3 hangs vertically over the left side of the horizontal tabletop. When the system is released from rest, block m¡ travels down the ramp with an unknown acceleration a. Assume the strings connecting the blocks remain taut so that the whole system travels with the same acceleration. a=? a=? m2= 4.00 kg FTi=? a=? Fr2=? Hz = 0.100 m¡ = 3.00 kg µj = 0.250 m3= 0.0250 kg 0= 37.0° (a) Draw a complete free-body diagram for each individual mass (three diagrams total). Be sure to label each force as well as the positive x- and y-axes on each diagram. Do not split forces into components. (b) Calculate the following forces: (i) The normal force acting on mị (ii) The normal force acting on m2 (iii) The kinetic friction force acting on m¡ (iv) The kinetic friction force acting on m2 (c) Calculate the following quantities: (i) The acceleration of the three-block system (ii) The tension Fri in the red piece of string (iii) The tension Fr2 in the blue piece of string (d) Suppose m3 were replaced with a different mass M that enabled the system to travel at constant velocity. What would the value of M have to be?
Two blocks with masses m1= 3.00 kg and m2=4.00 kg are connected by a light piece of red string. The red string is draped over a frictionless pulley. Block m, is positioned on a rough ramp that makes an angle of 37.0° with the horizontal, while block m2 is positioned on a rough horizontal tabletop to the left of the ramp. The coefficient of kinetic friction between mị and the ramp is µi= 0.250, and the coefficient of kinetic friction between m2 and the ramp is µ2= 0.100. Meanwhile, a third block of mass m3 = 0.0250 kg is connected to the other side of mass m2 with a piece of blue string. The blue string is draped over a second frictionless pulley so that mass m3 hangs vertically over the left side of the horizontal tabletop. When the system is released from rest, block m¡ travels down the ramp with an unknown acceleration a. Assume the strings connecting the blocks remain taut so that the whole system travels with the same acceleration. a=? a=? m2= 4.00 kg FTi=? a=? Fr2=? Hz = 0.100 m¡ = 3.00 kg µj = 0.250 m3= 0.0250 kg 0= 37.0° (a) Draw a complete free-body diagram for each individual mass (three diagrams total). Be sure to label each force as well as the positive x- and y-axes on each diagram. Do not split forces into components. (b) Calculate the following forces: (i) The normal force acting on mị (ii) The normal force acting on m2 (iii) The kinetic friction force acting on m¡ (iv) The kinetic friction force acting on m2 (c) Calculate the following quantities: (i) The acceleration of the three-block system (ii) The tension Fri in the red piece of string (iii) The tension Fr2 in the blue piece of string (d) Suppose m3 were replaced with a different mass M that enabled the system to travel at constant velocity. What would the value of M have to be?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
Please see the image attached. I only need part D. Thank you so much!
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Recommended textbooks for you
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON